K Street - 2003 Week 4 - 1.4 was released on: USA: 5 October 2003
"K" street
K=1
K Street.
If: 6x^2 +2x +k = 0 has equal roots Then using the discriminant of b^2 -4ab=0: 4 -24k=0 => k=-4/-24 => k=1/6 Therefore the value of k = 1/6
Kart racing is done in the street. It begins with the letter k.
k can have any value; however, the range of values permitted depends upon different things: The value of k depends on the value of x (ie given a value of x, the value of k can be calculated so that kx² + 4x + 5 = 0 has a root at that value of x): kx² + 4x + 5 = 0 => kx² = - 4x - 5 = -(4x + 5) => k = -(4x + 5)/x² Note that if x = 0, then the value of k is not determinable. Another possible answer using the discriminant of b²-4ac; from this the number of roots of the equation can be discovered: Two real roots: b²-4ac > 0 → 4² - 4×k×5 > 0 → 16 - 20k > 0 → 20k < 16 → k < 4/5 So for all values of k less than 4/5 there are two real roots of the quadratic kx² +4x + 5 = 0 One real repeated root: b² - 4ac = 0 → k = 4/5 So for k = 4/5, the quadratic (4/5)x² +4x +5 = 0 (→ 4x² +20x + 25 = 0) has one repeated real root. Two complex roots: b² - 4ac < 0 → k > 4/5 So for all values of k greater than 4/5 there are two complex roots of the quadratic kx² +4x + 5 = 0
As y is inversely proportional to x, the equation relating x to y is given by: y = k/x where k is the constant of proportionality. Using this we can find expressions for the value of y when x = 2 and x = 6 in terms of k: x = 2 → y = k/2 x = 6 → y = k/6 The difference between these is k/2 - k/6 = 3k/6 - k/6 = 2k/6 = k/3 But this, we are told is 5; thus: k/3 = 5 → k = 15 Thus y = 15/x Now that we have found the equation relating x to y, we can plug in the value for x = 4 and find the value of y: The value for y when x = 4 is y = 15/4 = 3.75
The duration of K. Street Pali Hill is 1440.0 seconds.
Little Green House on K Street ended in 1941.
Kansas, Kentucky, Kirkwood and Kemper are street names. They begin with the letter K.
K. Street Pali Hill ended on 2006-10-12.