Color blindness is an X-linked trait. That means it is carried in the X chromosome, which differentiates whether a baby will be a girl or a boy. Women have two X chromosomes (XX), and men have an XY combination. If a woman is a carrier for color blindness, only one of her chromosomes will be affected (we'll call it a little "x"), and for that reason she will not be colorblind. Men, on the other hand, only have one X chromosome, so any time they carry the colorblindness gene, they will be colorblind.
A child inherits one chromosome from each parent. He/She will get an X chromosome from his/her mother, and an X from her father (if a girl) or a Y from his father (if a boy).
So, If a woman is a carrier, Xx, and a man is normal, XY, they have several different chances for different offspring:
XX (a normal girl)
XY (a normal boy)
Xx (a normal girl who carries the colorblindness gene)
xY (a colorblind boy)
The short answer is, that if a woman has a boy, he has a 50% chance of being colorblind.
Color blindness is an X-linked trait, so if a mother is a carrier of the trait on one of her two X chromosomes, her female children have a 50% chance of carrying the trait but a 0% chance of being color blind. Her male children will have a 50% chance of being color blind and carrying the trait. The only way a female can display the trait of color-blindness is if her father is color-blind and her mother is a carrier of the trait.
vary likely
100% of all male offspring will be colorblind. 0% of all femal offspring will be colorblind.
homozygous
A homozygous dominant parent will produce gametes with the dominant allele only. Each gamete will carry one copy of the dominant allele.
A cross between two individuals that are homozygous for different alleles will only produce heterozygous offspring. This is because each parent can only donate one type of allele, resulting in all offspring being heterozygous for that particular gene.
No they will produce a child who is colour blind.
Organisms or genotypes that are homozygous for a specific trait and always produce offspring of the same phenotype are said to be true breeding. This means that when bred with another organism of the same genotype for that trait, all offspring will display the same characteristic.
There are two forms of Homozygous inheritance: Homozygous Dominant, and Homozygous Recessive. In order for two parents that are Homozygous to produce a Heterozygous offspring, one of them MUST be Homozygous Dominant, and the other MUST be Homozygous Recessive.
A normal homozygous individual can't produce offspring with sickle cell anemia. Both parents must carry the trait to have an offspring with the illness.
Yes, a horse with tobiano and sabino genetics can produce a homozygous tobiano foal - when bred to another horse with at least one tobiano gene.
homozygous recessive
The only genotype that can produce a recessive phenotype is homozygous for the recessive allele (aa). This means that both copies of the gene are the recessive allele, resulting in the expression of the recessive trait.
No, a homozygous ac plant cannot produce hydrogen cyanide (HCN) because the ac genotype is characterized by the absence of the necessary genes involved in cyanogenic glycoside biosynthesis. Therefore, plants with the ac genotype lack the ability to produce HCN.