CF4 and XeF4 do not violate the octet rule. In CF4, carbon forms four covalent bonds with fluorine, fulfilling the octet rule. In XeF4, xenon forms four covalent bonds with fluorine and has two lone pairs, also satisfying the octet rule.
SF4 is not a resonance structure; it is a molecular compound that consists of one sulfur atom covalently bonded to four fluorine atoms. Resonance structures involve the shifting of electrons within a molecule to generate different possible structures, but SF4 does not exhibit this property.
SF4 has a seesaw shape due to the presence of four substituents around the sulfur atom, causing the molecule to take on a trigonal bipyramidal geometry. The shape can be explained by considering the repulsion between the lone pair of electrons on sulfur and the bonding pairs, resulting in the bending of the molecule to minimize repulsion and achieve stability.
The shape of SF4 is Sea Saw
The chemical formula of sulfur tetrafluoride is SF4.
There is one set of lone pairs around sulfur in SF4.
CF4 is a covalent bond, because both elements are "nonmetals"
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The oxidation number for sulfur in SF4 is +4. This is because fluorine typically has an oxidation number of -1 and there are four fluorine atoms in SF4, resulting in a total charge of -4. Therefore, the sulfur must have a charge of +4 to balance the molecule.
VSEPR theory predicts the molecular geometry of a molecule by considering the repulsion between electron pairs around the central atom. In the case of SF4, there are five regions of electron density around the sulfur atom, leading to a trigonal bipyramidal geometry. However, one of the regions is a lone pair, causing greater repulsion and pushing the fluorine atoms closer together, resulting in a see-saw shape for SF4.
The SF4I2 molecule is nonpolar because the individual dipole moments of the SF4 and I2 molecules cancel each other out due to the symmetry of the molecule, resulting in a net dipole moment of zero.
The systematic name for SF4 is sulfur tetrafluoride.