Tin has 4 valence electrons. Because of this, Tin needs to lose the 4 electrons to make it stable. Thus the answer is SN4+
The electron configuration of beryllium is written as [He] 2s2. This means that it has 2s2 electrons above the configuration of Helium.
VanadiumAtomic number: 23Symbol: VAtomic weight: 50.9415(1)Electron configuration: [Ar]3d34s2Group: 5BPeriod: 4
1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 Rb+1 or Kr
Orbital notation shows how the electrons are arranged in the orbitals of the sublevels. Electron configuration shows only how many electrons are in each sublevel.
It is used to determine the electron configuration of an atom, molecule or ion.
Tin. {http://en.wikipedia.org/wiki/Tin}.
Silver forms anions by losing one electron to achieve a stable electron configuration. Strontium typically forms cations by losing two electrons to achieve a stable electron configuration. Tin can form both cations and anions, depending on the reaction conditions. Iodine often forms anions by gaining one electron to achieve a stable electron configuration.
It could be either Sn2+ ion (stannous ion) or Sn4+ ion (stannic ion)
The ion formed when sodium achieves a stable electron configuration is Na+ (sodium ion). Sodium (Na) loses one electron to achieve a stable electron configuration similar to that of neon.
The symbol for a chlorine ion that has gained one electron to achieve a stable electron configuration would be Cl-.
Although the formation of an octet is the most stable electron configuration, other electron configurations provide stability. These relatively stable electron arrangements are referred to a pseudo-noble gas configuration. Although the formation of an octet is the most stable electron configuration, other electron configurations provide stability. These relatively stable electron arrangements are referred to a pseudo-noble gas configuration.
The electron configuration of tin is [Kr]5s24d10. The electron configuration of Cr2+ is [Ar]3d4. When chromium loses two electrons to form Cr2+, the 4s electrons are removed before the 3d electrons.
5s25p2 The 2's are exponents on the s and the p
The group of elements that have a stable electron configuration are the noble gases.
False. Alkali metals lose one electron to form a stable electron configuration with a full outer shell of electrons, which is the stable electron configuration for these elements.
The noble gas configuration for fermium (Fm) is [Rn] 5f12 7s2. It represents the electron configuration of fermium in a stable state, where it mimics the electron arrangement of the noble gas radon (Rn) to achieve a more stable configuration.
The electron configuration of boron is 1s2 2s2 2p1. When boron becomes an ion, it typically loses its outer electron to achieve a stable electron configuration. Therefore, the electron configuration of a boron ion is typically 1s2 2s2.