Lead iodide can be obtained as a yellow precipitate by reacting solutions oflead(II) nitrate and potassium iodide the other compound created by the reaction is potassium nitrate which is a white power but as it is soluble it does not form a precipitate. 2KI + Pb(NO3)2 --> 2KNO3 + PbI2 the balanced equation if you were needing it
your name! lol i have heard this riddle dozens of times b4.
CaNr2 name
khankirpola
It is scientific name for humans. Scientists have developed a system to name all the species on this planet. Each animals has a species name and a genus name.
Potassium iodide.
Cl2 + 2KI → 2KCl + I2
Pb(NO3)2(aq) + 2KI)aq) = 2KNO3(aq)+ PbI2(s) PbI2 is a yellow coloured solid and will precipitate out of the solution.
The balanced symbol equation between chlorine and potassium iodide is: Cl2 + 2KI -> 2KCl + I2
The balanced symbol equation between fluorine and potassium iodide is: 2KI + F2 --> 2KF + I2
The balanced equation for the reaction is: 2KI + Cl2 -> 2KCl + I2
2KI + Cl2 = 2KCl + I2
2ki + h2o2 = 2koh +i2
The reaction between potassium iodide (KI) and dilute sulfuric acid (H2SO4) can be represented by the following equation: 2KI + H2SO4 -> 2KHSO4 + HI
When fluorine reacts with potassium iodide, potassium fluoride and iodine are produced. The balanced chemical equation for this reaction is: 2KI + F2 -> 2KF + I2.
The balanced chemical equation for the reaction between chlorine gas (Cl2) and potassium iodide (KI) is: Cl2 + 2KI --> 2KCl + I2
2KI + HgCl₂ -----> 2KCl + HgI₂