1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6
Rb+1 or Kr
VanadiumAtomic number: 23Symbol: VAtomic weight: 50.9415(1)Electron configuration: [Ar]3d34s2Group: 5BPeriod: 4
In the atom a proton has the charge +1 and the electron the charge -1.
The neutral atom with 44 electrons is ruthenium (Ru).The electron configuration of ruthenium is: [Kr]4d75s1.The number of electrons in shells is: 2, 8, 18, 15, 1.
In this context, we call an electron a beta particle.
In period 3? It has to be Boron although technically it is not a gas. The electron configuration is either 2, 3 or 1s^2, 2s^2, 2p^1 depending on what level of chemistry you are working at. If the latter looks like a different language you to, go with the first! that is actually wrong above^^, the real answer is argon so its electron configuration is 1s2, 2s2, 2p6, 3s2, 3p6
In the Rb atom, the electron configuration is [Kr]5s^1. This means there is 1 electron in the 5s sublevel of the Rb atom.
Rubidium (Rb) has a +1 ion, will have the same electron configuration as krypton (Kr) because the +1 status means it has lost an electron. The configuration is written 1s22s22p63s23p64s23d104p6.
The charge for Rubidium (Rb) is typically +1, as it tends to lose one electron to achieve a stable electron configuration.
Rb ions have a charge of +1, as they lose one electron to achieve a stable electron configuration.
The electron configuration of Cu+1 is [Ar] 3d10 4s1. When copper loses one electron to become a +1 ion, it loses the 4s electron first, followed by one of the 3d electrons to attain a stable electron configuration.
Rubidium forms a +1 cation (Rb+) by losing one electron to achieve a stable electron configuration. Rubidium has one valence electron in its outermost shell, so by losing this electron, it becomes a cation.
Alkali metals such as Li, Na, K, Rb, Cs, and Fr each have 1 valence electron. This is because they have a single electron in their outermost electron shell, making them highly reactive and likely to lose that electron to achieve a stable electron configuration.
Rubidium has one valence electron in the 5s orbital.
Fr is in the 1st period. It removes an electron to get noble gas configuration. Fr+ does not have valence electrons.Francium has 1 electron in its outermost energy level. It donates its outermost electron to stabilize its electron configuration. Francium(I) has no valence electrons.
Rubidium (Rb) has 1 valence electron. This is because it is in the first group (group 1) of the periodic table, which means it has 1 electron in its outermost shell.
The electron configurations of H, Li, Na, K, Rb, and Cs are similar in that they all have one valence electron in their outermost energy level. These elements belong to the alkali metal group in the periodic table and tend to exhibit similar chemical properties due to their outermost electron configuration.
Fluorine's electron configuration is 1s2 2s2 2p5, and since fluoride is just fluorine with an extra electron, or F-1, its electron configuration is 1s2 2s2 2p6.