r3hk7
No, the scientific method can be uncontrolled to for it to be valid.
a valid investigation is an effective investigation i think. The results turn out to be what you had inferred.
newtons laws are always valid in non inertial frames
Sorry but your question doesn't make sense... You have to know what the hypothesis is to test if your question is valid.
The electron configuration of uranium is: [Rn]5f36d17s2.
The electron Configuration [Ra] 7s2 5f8 is Not Valid because Ra is basically [Rn] 7s2. However, you have Ra 7s2 5f8. You can never repeat and electron configuration piece twice, or at all.
In uranium-238, the highest sublevel that electrons occupy is the 5f sublevel. Uranium has 92 electrons, so the electron configuration would be [Rn] 5f3 6d1 7s2.
[Rn]7s2
Ra, radium
The noble gas configuration for uranium is [Rn] 5f3 6d1 7s2. This means that the electron configuration for uranium can be shortened to make it like a noble gas (radon) by including the noble gas before uranium in square brackets.
Electron configuration of uranium: 5f3 6d1 7s2 See also: http://en.wikipedia.org/wiki/Atomic_electron_configuration_table
The electronic configuration of uranium is Rn 5f3 6d1 7s2 because uranium has 92 electrons. Electrons fill up the orbitals with the lowest energy level first (Aufbau principle), and the 5f, 6d, and 7s orbitals are progressively filled in that order for uranium.
Uranium has valences 2, 3, 4, 5, 6.Valence electrons are located on the levels 5f3, 6d1, 7s2.
Uranium atom has 7 electron shells with 2, 8, 18, 32, 21, 29, 2 electrons.The electron configuration is [Rn]5f3 6d1 7s2.
1s²2s² 2p63s² 3p6 3d104s2 4p6 4d10 4f145s2 5p6 5d10 5f46s2 6p67s2Edited by Progassman from this point on:The diagram above is not the electron configuration of Uranium (U). It is the Aufbau Principle with the number of electrons it can hold in every sublevel. The real configuration is 1s2,2s2 2p6,3s2 3p6 3d10, 4s2 4p6 4d10, 5s2 (from here on, I am not sure but I am sure about the short hand) 5p6 5d10 5f3, 6s2 6p6 6d1, 7s2. The short hand method is [Rn] 5f3 6d1 7s².
The total number of electrons in the outer shell of uranium is 2 electrons. Uranium has an atomic number of 92, which means it has 92 electrons. The electron configuration for uranium is [Rn] 5f3 6d1 7s2, so the electrons in the outermost shell are the 7s2 electrons.