Assuming liquid gallons... 0.0002641720524 gal Algebraic Steps / Dimensional Analysis Formula 1 cm³*1 l 1000 cm³*33.814 fl.oz. 1 l*1 gal 128 fl.oz.=0.0002641720524 gal Direct Conversion Formula 1 cm³*1 gal 3785.411784 cm³=0.0002641720524 gal
Yes.1 L is defined as 1 cubic decimetre. A decimetre is 0.1 m or 10 cm.10 cm × 10 cm × 10 cm = 1000 cm³Notes:There are 1000 L in 1 cubic metre (m³)There are 1000 millilitres (mL) in a litre.1 mL = 1 cm³.
we know,perimeter of rectangle = 2 * ( l+b) perimeter= 2 *(45+30) = 2 * 75 =150 cm
how many cm in 1 inch
1 yard =91.44 cm
1 L = 1000 mL = 1000 cm cubed
Infinitely many. Select any number, L, such that 12 < L < 24. Let W = 24 - L. Then a rectangle with sides of length L cm and width W cm will have a perimeter of 48 cm. And since the choice of L was arbitrary, there are infinitely many possible values of L and thence infnitely many rectangles.
There are 100cm in a metre.
1 l = 1000 cm³ → 0.75 l = 0.75 x 1000 cm³ = 750 cm³ (1 cm³ = 1 ml)
If the distance of L from F is ≥ 6 cm then the answer is 2. If the distance of L from F is < 6 cm then the answer is 1.
Any number greater than or equal to 4*sqrt(45) cm or 26.83 cm (approx). To see that, suppose L ≥ sqrt(45) cm be the length of the rectangle and let B = 45/L cm Then Area = L*B = L*(45/L) = 45 cm2 If L = 9cm, then B = 45/9 = 5 cm and then perimeter = 2*(L+B) = 28 cm If L = 90 cm, then B = 0.5 cm and P = 181 cm If L = 900 cm, then B = 0.05 cm and P = 1800.1 cm If L = 9000000 cm then B = 0.000005 cm and P = 18000000.00001 cm As can be seen, the perimeter can be increased without limit.
If 150 / x = 66, then x = 2.2727 cmSuppose the length is L cm.Then 150*L cm = 66 cmSo L cm = 66 cm/150 = 66/150 cm = 0.44 cm = 4.4 mm.
1 litre = 1000 cm3
You cannot convert liquid to length.
L = ( 45 cm ) ( 1.0 in / 2.54 cm ) ( 1.0 ft / 12 in ) = 1.48 ft
Suppose length is L cm. Then Width = L-15 cm Perimeter = 2*(W+L) = 2*(L-15 + L) = 2*(2L - 15) = 4L - 30 cm So 4L - 30 = 98 so that 4L = 128 and then L = 32 cm Then W = L - 15 = 32- 15 = 17 cm. So the rectangle is 32 cm * 17 cm
The length of the diagonal is not enough to determine the dimensions of the rectangle. Take any length W such that 0<W<sqrt(132/2) that is, 0<W<9.192 cm. And let L = sqrt(132 - W2) cm. Then 9.192<L<13 so that any combination of W and L is unique. There are infinitely many possible values for W and so infinitely many different combinations for W and L. That is, infinitely many rectangles whose width is W cm and length is L cm. And, since, L2 = 132 - W2, L2 + W2 = 132 so the diagonal is 13 cm.