Any value - you must supply the resistance.
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The amperage drawn from batteries is governed by the connected load. The voltage of the batteries can be one of two voltages. in parallel the 8 batteries will give you a voltage of 6 volts. In series the 8 batteries will give you a voltage of 48 volts. The amp/hour capacity of the batteries will give you the amount of current the device can draw over a specific length of time. Equation to fine amperage is I = W/E, Amps = Watts/Volts. Watts = Amps x Volts.
The formula is P = E x I. Power in watts (P) is equal to the product of the voltage (E) and the current (I). The total power used at 6 amps and 120 volts is equal to 720 watts. If the voltage was 240 volts, the total power would be 240 volts times 6 amps, or 1440 watts.
A 12 ohm resistor with 6 volts across it will dissipate 3 watts of power. Current = voltage divided by resistance = 6 / 12 = 0.5 amperes. Power = voltage times current = 6 * 0.5 = 3 watts.
UK Mains is 230V therefore 6 KW is 6000/230 = 26 Amps. 3 phase is slightly different....... 6000/400V = 15 Amps/root 3 = 8.67 Amps per phase.
A 16 mm squared wire is equal to a #5 on the AWG scale. The electrical code book does not have amperage capacities for odd numbered wires. In North America the #6 copper conductor with an insulation factor of 75 or 90 degrees C is rated at 65 and 75 amps respectively. A #4 copper conductor with an insulation factor of 75 or 90 degrees C is rated at 85 and 95 amps respectively.