To get 100g of solution: 10g of sodium thiosulfate + 90g of water.
Dakn's solution is approx 0.5% sodium hypochlorite (household bleach diluted 1:10) plus a small amount of sodium bicarbonate.
simply make the solution of sodium sulfide and sodium hydroxide in water, 105% solution is enough, either deep for few hours or poass electric DC current 1V for instant results.## Alpesh UK
oxidation-reductionWhat type of a reaction occurs when a sodium hydroxide solution is mixed with an acetic acid solution?The answer above is wrong. The correct answer is acid-base neutralization
A solution is a mixture of a solute and a solvent. A common solvent is water and an example of a solute is salt (sodium chloride). Adding salt to water results in a salt solution, sometimes called a saline solution. A solution will be in one phase, normally a liquid but solutions can be found as gasses and as solids. Note that a mixture of two substances that do not form a single homogeneous substance is not a solution. Sand and water don't make a solution and a mixture of dry sugar and salt also don't make a solution.
Well to make 30% stock solution of BSA from powder form you need to dissolve 30g of BSA into 100ml of solvent (water). Thus dissolved solution becomes 30% (w/v) stock solution.
To prepare 0.02M sodium thiosulfate solution, weigh out the required amount of sodium thiosulfate pentahydrate (Na2S2O3·5H2O) or anhydrous sodium thiosulfate (Na2S2O3). Dissolve this in distilled water and make up the volume to the desired concentration. Make sure to use a volumetric flask for accuracy and precision in preparing the solution.
To prepare 0.01N sodium thiosulfate per Indian Pharmacopoeia (IP) standards, dissolve 25.3 grams of pure sodium thiosulfate pentahydrate (Na2S2O3·5H2O) in distilled water to make 1000 ml of solution. This solution will have a normality of 0.01N.
To prepare a 0.002M sodium thiosulfate solution, dissolve the appropriate amount of sodium thiosulfate pentahydrate (Na2S2O3·5H2O) in distilled water to make the desired volume of solution. Calculate the molarity using the formula M = (mol/L) and adjust as needed. Make sure to accurately measure and mix the components to ensure a homogeneous solution.
To prepare a 0.01N solution of sodium thiosulfate, dissolve 2.48 grams of sodium thiosulfate pentahydrate (Na2S2O3·5H2O) in distilled water and make up the solution to 1 liter. This solution will be approximately 0.01N in strength. Remember to accurately weigh the compound and use a volumetric flask for precise dilution.
To prepare a 0.05 Normal solution of sodium thiosulfate, you would dissolve the appropriate weight of sodium thiosulfate pentahydrate in a known volume of water to achieve a concentration that corresponds to 0.05 N. The molar mass of sodium thiosulfate pentahydrate (Na2S2O3·5H2O) is 248.18 g/mol. You can calculate the weight needed using the formula: (Normality) x (Equivalent weight) x Volume = Weight of the compound.
To prepare N 80 thiosulfate, dissolve 80 grams of sodium thiosulfate pentahydrate (Na2S2O3·5H2O) in enough distilled water to make a final volume of 1 liter. Stir the solution until the thiosulfate is completely dissolved. Ensure that the solution is mixed well and store it in a properly labeled container. Always follow safety protocols when handling chemicals.
To make a 2% sodium hypochlorite solution from a 12% solution, you can set up the equation: 12% solution * x litres = 2% solution * 100 litres Solving for x, you get: x = (2% solution * 100 litres) / 12% = 16.67 litres Therefore, you would need 16.67 litres of the 12% sodium hypochlorite solution to make 100 litres of a 2% solution.
To make 10 gallons of a 50% sodium hydroxide solution, you would need 10 pounds of sodium hydroxide. This is because the percentage indicates the weight of sodium hydroxide in the solution. Hence, in a 50% solution, half of the weight of the solution is sodium hydroxide.
To make a 9 percent saline solution, start by preparing a 100 percent salt solution. With a bottle of 100 percent salt water, take 9 percent and dilute with distilled water to make a 9 percent saline solution.
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To calculate the grams of sodium thiosulfate needed, first determine the molar mass of Na2S2O3 (158 g/mol). Step 1: Calculate the number of moles needed using the formula: moles = Molarity * Volume (in liters) moles = 0.025 * 2 (since 2000 ml is 2 liters) = 0.05 moles Step 2: Calculate the grams needed using the formula: grams = moles * molar mass grams = 0.05 * 158 = 7.9 grams Therefore, you would need 7.9 grams of sodium thiosulfate to make 2000 ml of a 0.025N solution.
To make a 7.5% solution of sodium carbonate in water, add 7.5 grams of sodium carbonate to 100 mL of water and stir until the sodium carbonate is completely dissolved. This will give you a 7.5% (w/v) solution of sodium carbonate.