The glow of the bulb is due to heating of the filament to the incandescent level. Joule's heating effect gives the formula H = I2 R t.
Hence more the current then more the heat and so more brightness. Thus large current makes the bulb brighter no doubt. At the same time if current exceeds the nominal level then filament would get melted and get fused.
If a circuit is wired in parallel, all the bulbs have their own independent access to electricity, so if one bulb goes out, the others are not affected. If the circuit is wired in series, then one bulb going out will block the current to all the other bulbs as well.
When you add a light bulb, you are adding a load, which performs a function - in this case, it converts electrical energy to light and heat energy. When you add an ammeter, most of the time you intend to measure the current in the circuit, which is the function of the ammeter. Thus the two electrical components differ in their function and does different things when added to a circuit.
in a series circuit current flows through each resistor or light bulb and if one item burns out the complete circuit goes dead such were the old fashioned xmas tree lights. They were wire in series and if one light burned out you had to test each light bulb til you found the one burned out to get the whole string to work again. In a parallel circuit each resistor, motor, light bulb has its own ground so if you lost one light in a circuit the rest of them continue to burn.
The bulb becomes brighter unless it is too much till it shot-circuits.
If you have a 3 bulbs in parallel lets say. If one of those burns out it just means that there is now an open circuit where the burned out bulb used to be. The two that remain aren't aware that anything has changed.
Adding another bulb in series will increase the total resistance in the circuit, causing the current to decrease. As the current decreases, the brightness of both bulbs will decrease since they will receive less power.
In a series circuit, if one bulb goes out, the circuit is considered open because the current flow is interrupted and cannot continue through the circuit.
You know if current is flowing in a bulb circuit because, if there is enough power (voltage times current), the bulb will illuminate. If there is current, but not enough power to illuminate the bulb, you will need to measure the current with an ammeter to see if there is any current.
A series circuit is where there is only one path for the current. As a result, and as a direct consequence of Kirchoff's current law, the current at every point in a series circuit is the same. The two bulbs have the same current flowing through them.
A switch is used of stop the current flow in a circuit and the bulb can be classed as the load in a circuit.
If the bulb is of the incandescent variety, then reducing the current in the circuit will do this.
If the bulb is removed from its holder, the circuit will be open, breaking the flow of electricity. This will result in the current being unable to pass through the circuit and the bulb will not light up as a result.
The resistance of the new bulb is likely higher than the previous bulb. Increasing resistance in a series circuit decreases current flow. When resistance increases, less current can flow through the circuit, resulting in a decrease in current.
Think of it this way: If you want a lot of water to flow into one place, would you divide the river? However, it's irrelevant in this case, because the light bulb can only take a certain amount of current and voltage before it burns out. You can have amazingly bright for a millisecond or fairly bright for a long time. Your choice.
Current in a series circuit is the same throughout the circuit. Voltages are additive. Voltage in a parallel circuit is the same throughout the circuit. Currents are additive.
Too much current for the rating of the bulb.
The failed bulb breaks the circuit so no current can flow - so the other bulb goes out (but is OK).