This question can be answered with the equation n = m ÷ M (where n is the number of mol's, m is te mass in grams and M is the Molar Mass of Sodium Chloride). Now, sodium chloride's molecular formula is written as, NaCl Now if we think of this formula as representing a ratio of elements within the compound, we can see that, NaCl : Cl = 1 mole of sodium chloride molecules : 1 mole of Chloride atoms So, as we know the mol ratio for this molecule, we can establish the mass of sodium in 11.7g of sodium chloride by first calculating the number of moles of Sodium chloride in 11.7g of the substance, so then moles = mass of sodium chloride ÷ Molar mass of sodium chloride = 11.7 ÷ 58.44277 = 0.20019584971759552122529442050745 moles (note that in stochiometry i personally prefer not to round numbers until the end of the question Now by applying this number to the mol ratio, we can calculate the number of moles of sodium in sodium chloride 1 mole of sodium chloride molecules : 1 mole of Chloride atoms =0.20019584971759552122529442050745 : 0.20019584971759552122529442050745 Now that we have established that the number of moles of of sodium in 11.7g of sodium chloride is 0.20019584971759552122529442050745 mol, the mass of sodium in 11.7g of sodium chloride can be calculated with the formula, m = n M = mass of sodium in 11.7g of sodium chloride = 0.20019584971759552122529442050745 X 23 = 4.6045045435046969881817716716713g (all decimal places)
26 g sodium chloride contain 10,313 g sodium.
The mass is 58,44 g NaCl.
100 g of the solution contains 11 g of sodium chloride
To find the number of moles in 117g of sodium chloride, you need to first calculate the molar mass of NaCl, which is 58.44 g/mol. Then, divide the given mass (117g) by the molar mass to get the number of moles. So, 117g / 58.44 g/mol = 2 moles of sodium chloride.
The molecular mass of sodium chloride is 58,44 g.
The total mass of the solution is 20 g (sodium chloride) + 380 g (water) = 400 g. The mass percent concentration of sodium chloride in the solution is (20 g / 400 g) * 100% = 5%.
The molecular weight of sodium chloride is 58,44 (rounded).
Sodium chloride has a molar mass of about 58.5 g/mol. So multiply 8 moles by molar mass to get about 468 grams.
The chemical formula of sodium chloride is NaCl. The formula mass is calculated by adding the atomic masses of sodium (Na) and chlorine (Cl), which are 22.99 g/mol and 35.45 g/mol, respectively. Therefore, the formula mass of sodium chloride is approximately 58.44 g/mol.
The answer is 2080,46 g.
50 g sodium chloride (NaCl) contain 30,167 g chlorine.
To find the number of moles in 585 g of sodium chloride, we first need to determine the molar mass of NaCl. Sodium has a molar mass of approximately 23 g/mol, and chlorine has a molar mass of approximately 35.5 g/mol. Adding these together gives a molar mass of approximately 58.5 g/mol for NaCl. Dividing the given mass (585 g) by the molar mass gives us approximately 10 moles of sodium chloride.