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To get 0.15 moles of NaCl,

mass of NaCl = moles * molar mass

= 0.15 * (23+35.5)

= 8.775 g

and 0.15M is 0.15 mole of NaCl in on liter solvent which equals 8.775 g then ypu add solvent up to 1 liter.

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15y ago
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10y ago

0,15 M NaCl equal a concentration of 8,776 g/L.

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10y ago

The answer is 4,383 g.

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Q: How much NaCl require for 0.15M nacl solution?
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The concertration of a water solution of NaCl is 2.48m and it contains 806 g of water How much NaCl is in the solution?

To determine the amount of NaCl in the solution, you first need to calculate the moles of NaCl present. Using the given molarity (2.48 M) and the volume of the solution (assumed to be 806 g = 806 ml for water), you can find the moles of NaCl. Then, you convert the moles of NaCl to grams using the molar mass of NaCl (58.44 g/mol) to find the amount of NaCl in the solution.


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To determine the grams of NaCl in 0.058% NaCl solution, you first convert 0.058% to a decimal by dividing by 100 (0.00058). Then, you set up a proportion to find out how much of the solution contains 1.5g of NaCl. 1.5g of NaCl is equivalent to 0.00058x, where x is the total grams of solution. Solve for x to find how much of the solution is needed.


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You want 1 liter of 0.1 M NaCl and you have 4 M stock solution How much of the 4 M solution and how much dH2O will you measure out for this dilution?

To make 1 liter of 0.1 M NaCl solution, you will need 25 ml of the 4 M NaCl stock solution and 975 ml of water. This will give you the desired concentration of 0.1 M NaCl in a total volume of 1 liter.


How much 2M Nacl solution would you need to make 250ml of 0.15M Nacl solution?

To prepare 250 ml of 0.15M NaCl solution, you would need 10 ml of 2M NaCl solution. This can be calculated using the formula: (C1V1 = C2V2), where C1 is the initial concentration, V1 is the initial volume, C2 is the final concentration, and V2 is the final volume.


How much nacl is required for a 200 mM NaCl solution?

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How much 0.075 M NaCl solution can be made by diluting 450 mL of 9.0 M NaCl?

To find the volume of 0.075 M NaCl solution that can be made, you can use the formula C1V1 = C2V2. Plugging in the values, we get (9.0 M)(450 mL) = (0.075 M)(V2). Solving for V2 gives V2 = 1.1 L. Therefore, 1.1 L of 0.075 M NaCl solution can be made by diluting 450 mL of 9.0 M NaCl.


How much sodium chloride needed to make 10ppm sodium solution?

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How much NaCl is required for 100 mM NaCl solution?

To prepare a 100 mM NaCl solution, you would need to dissolve 5.84 grams of NaCl in water to make a final volume of 1 liter. This calculation is based on the molar mass of NaCl (58.44 g/mol) and the definition of molarity (Molarity = moles of solute / volume of solution in liters).


What is the molarity of sodium sulphate in a solution prepared by dissolving 15.5g in enough water to make 35ml of solution?

To find the molarity of the solution, first calculate the number of moles of sodium sulfate by dividing the mass (15.5g) by the molar mass of sodium sulfate (142.04 g/mol). Next, convert the volume of the solution to liters (35 ml = 0.035 L). Finally, divide the number of moles by the volume in liters to get the molarity of sodium sulfate in the solution.


Will elevation in boiling point be same for 0.1 m NaCl and 0.1m sucrose solution?

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How much would the freezing point of the water decrease if 4 mol of NaCl were added to 1 kg of water for water and i 2 for NaCl?

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