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How much hcl gas can be produced at stp by reacting 131 g of nacl with excess h2so4?
Using the equation: 2 NaCl + H2SO4 -> 2 HCl + Na2SO4, we can see that 1 mole of NaCl will produce 1 mole of HCl. First, calculate the moles of NaCl (131g / 58.44g/mol). Then, using the mole ratio from the equation, you can find the moles of HCl produced. Finally, using the ideal gas law, you can convert the moles of HCl to volume at STP.
How much NaCl precipitate would be produced if 2 molarity HCl and 1 molarity sodium carbonate react in the reaction Na2CO3 plus 2HCL yields 2NaCl plus H2O plus CO2?
2 moles or 117 gram of NaCl is precepitated
How much of NaCl is in 1.31 L of 0.300 M NaCl?
1.31*.3=.393 mols NaCl. This also equals .393(22.99+35.45)=22.97 g NaCl.
How much Elemental chloride in NaCl?
The formula unit of sodium chloride (NaCl) contain 60,33 % chlorine.
How much iodine was put in NaCl?
The recommended concentration is 20 +/- 5 mg iodine/kg NaCl.
How much gNacl and how much gwater needed for ready of 500g solution of NaCl 0.95 percent?
0.95% * 500 g = 4.75 g NaCl
Determine how much of each of the following NaCl solutions in grams contains 1.5g of NaCl 0.058 percent NaCl by mass?
To determine the grams of NaCl in 0.058% NaCl solution, you first convert 0.058% to a decimal by dividing by 100 (0.00058). Then, you set up a proportion to find out how much of the solution contains 1.5g of NaCl. 1.5g of NaCl is equivalent to 0.00058x, where x is the total grams of solution. Solve for x to find how much of the solution is needed.
How much nacl is required for a 200 mM NaCl solution?
You need 58,44 mg of ultrapure NaCl; dissolve in demineralized water, at 20 0C, in a thermostat, using a class A volumetric flask of 1 L.
How much NaCl precipitate would be produced if 2 molarity HCl and 1 molarity sodium carbonate react in the reaction Na2CO3 plus 2HCL yeilds 2NaCl plus H2O plus CO2?
Since the balanced chemical equation states that 1 mole of sodium carbonate reacts with 2 moles of HCl to produce 2 moles of NaCl, the theoretical yield of NaCl would be double the initial moles of HCl used. Given the molarity of HCl, you can calculate the moles of NaCl produced and convert to grams if the volume of the solution is known. Remember to consider stoichiometry when doing the calculation.
The concertration of a water solution of NaCl is 2.48m and it contains 806 g of water How much NaCl is in the solution?
To determine the amount of NaCl in the solution, you first need to calculate the moles of NaCl present. Using the given molarity (2.48 M) and the volume of the solution (assumed to be 806 g = 806 ml for water), you can find the moles of NaCl. Then, you convert the moles of NaCl to grams using the molar mass of NaCl (58.44 g/mol) to find the amount of NaCl in the solution.
How much keratin is produced?
how much is keratine produced?
How much of NaCl is in 1.84 L of 0.200 M NaCl Answer in units of mol.?
To find the amount of NaCl in 1.84 L of 0.200 M NaCl, you use the formula: amount = concentration x volume. Thus, amount = 0.200 mol/L x 1.84 L = 0.368 mol of NaCl.
