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How many moles of NaCl is required to make 1L of a 140mM solution?
To find the moles of NaCl needed, first convert 140 mM to M by dividing by 1000. Then, use the formula moles = Molarity x Volume (in liters) to calculate the moles required. In this case, the calculation would be: 0.140 mol/L x 1 L = 0.140 moles of NaCl.
How many moles of sodium chloride are in 5.08 L of a 2.36 M solution?
To find the number of moles of sodium chloride, you can multiply the volume of the solution by its molarity. moles = volume (L) * molarity moles = 5.08 L * 2.36 mol/L moles = 11.9928 mol Therefore, there are approximately 11.99 moles of sodium chloride in 5.08 L of a 2.36 M solution.
How many moles of NaCl are contained in 100o ml of a 0.20 M solution?
To find the moles of NaCl, first convert the volume to liters: 1000 ml = 1 L. Then use the formula moles = Molarity x Volume (in liters) to calculate the number of moles. So, moles = 0.20 mol/L x 0.1 L = 0.02 moles of NaCl.
What is the mole concentration of 58.44g of NaCl in 1 L of water?
Molarity = moles of solute/Liters of solutionGet moles NaCl.58.44 grams NaCl (1 mole NaCl/58.44 grams)= 1 mole NaCl------------------Molarity = 1 mole NaCl/1 liter= 1 M NaCl========
What is the molarity of a 2.000 L solution thatis made from 14.60 g of NaCL?
Find moles NaCl first.14.60 grams NaCl (1 mole NaCl/58.44 grams)= 0.2498 moles NaCl================Now,Molarity = moles of solute/Liters of solutionMolarity = 0.2498 moles NaCl/2.000 Liters= 0.1249 M NaCl solution--------------------------------
100ml of 0.200 molL NaCl is mixed with 400ml of 0.200 molL NaCl What is the concentration of Cl in the resulting solution?
The total moles of NaCl in the solution is 0.2 mol/L * (0.1 L + 0.4 L) = 0.3 moles. Since NaCl dissociates into 1 Na+ ion and 1 Cl- ion, the total moles of Cl- ions is also 0.3 moles. The concentration of Cl- ions in the resulting solution is 0.3 moles / (0.1 L + 0.4 L) = 0.6 mol/L.
What is the molarity of a 3000 liters solution containing 300 grams of NaCl?
To calculate the molarity, you first need to convert the mass of NaCl to moles. The molar mass of NaCl is 58.44 g/mol. Therefore, 300 grams of NaCl is equal to 300/58.44 = 5.13 moles. Next, divide the moles of NaCl by the volume of the solution in liters (3000 L) to get the molarity, which is 5.13 moles / 3000 L = 0.00171 M.
How do you find the total mass of NaCl in a 455000L pool at a constant concentration of 0.048 M?
You start by checking how many moles of NaCl you have in your pool. Number of moles=concentration*volume =0.048mole/L*455000L=21840moles Then you get the molar mass of NaCl which is 58.443 g/moles, then you multiply it by your number of moles. 21840 moles*58.443g=1'276'395g=1'276.395kg of NaCl
How many moles per mL of the solute are contained in the 0.20 M NaCl?
0.0002 mol NaCl/mLmolarity = (moles solute)/(L of solution)0.20 M NaCl = 0.20 mol NaCl/L1 L = 1000 mL0.20 mole NaCl/1000 mL = 0.00020 mol NaCl/mL (rounded to two significant figures)
What is the concentration M of a NaCl solution prepared by dissolving 3.8 g of NaCl in sufficient water to give 245 mL of solution?
The molar mass of NaCl is 58.44 g/mol. First, calculate the number of moles of NaCl by dividing the mass (3.8 g) by the molar mass. Then, calculate the molarity by dividing the moles of NaCl by the volume of the solution in liters (245 mL = 0.245 L). Molarity (M) = moles of solute (NaCl) / volume of solution (L).
Why is 0.9 NaCl osmolarity 300 mOsmL calculations?
- 0,9 g/L NaCl equal to 0,154 moles - but because NaCl is dissociated in two ions in water the relation is 1 mol NaCl equal 2 osmol/L - and so 0,9 % NaCl equal 308 milliosmole/L
How many grams of NaCl are in 1.92 moles of NaCl?
Every mol of NaCl contains a mol of Na, weighting 23 grams, and a mol of Cl, weighing 35.5 grams. So, every mol of NaCl weights 58,5 (=23+35.5) grams. Therefore, 145 moles of NaCl weights 8482.5 grams.
