Wiki User
∙ 8y ago40.8 grams
Wiki User
∙ 8y agohow many grams of glucose must be added to 525g of 2.5 percent leg mass glucose solution?and give the furmela?
12*(90%)=10.8=X*.25 10.8/.25=X=43.2 43.2-12=31.2 31.2 grams of water must be added
195 grams.
To convert the solution from m percent salty to 2m percent salty, you need to add m/2 grams of salt. This will ensure that the ratio of salt to water in the solution is doubled, resulting in a 2m percent salty solution.
The percent concentration is 13,75 %.
Very simply 1g of ammonium thiocyanate and 100g (100ml) of water!
You have 100 grams of pure dextrose and 9 grams of pure sodium chloride added to one liter of distilled water. The solution is sterilized and packed in polypropylene or polyethylene bottles.
No, the mass percent concentration is a ratio of the mass of the solute to the total mass of the solution, expressed as a percentage. It is calculated by dividing the mass of the solute by the mass of the solution (solute + solvent) and multiplying by 100.
The answer is 0.8 L: Let's think of a '6/15 solution' as meaning 6/15 grams per litre, and the solution we're trying to obtain is 10 grams/litre. In our final solution, we'll have 6 grams resulting from the one litre of weaker solution, and 15v grams from the stronger (where v is the volume of stronger added). Deviding this total mass by the total volume of the solution, we arrive at the wanted concentration of 10 grams/litre. Algebraicly: (15v + 6)/(1+v) litres = 10 15v + 6 = 10 + 10v 5v = 4 v = 4/5 = 0.8 L Hope this helps.
The weight of 10 percent acetic acid solution would depend on the total volume of the solution. For example, if you have 100 grams of a 10 percent acetic acid solution, it would contain 10 grams of acetic acid.
This is (mass of solute) divided by (mass of total solution) expressed as a percentage. The solute is what you are dissolving into the solution. Example: you have 90 grams of water, and you add 10 grams of salt (sodium chloride). The water is the solvent, sodium chloride is the solute, and the solution is salt water. 90 grams + 10 grams = 100 grams (mass of total solution). (10 grams) / (100 grams) = 0.1 --> 10% mass mass percent concentration.
It would be 12.6g of IKI to obtain the 100mL solution of 0.300 M IKI.