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1.Weigh 292,2 g ultrapure NaCl dried at 110 0C for 30 min.
2. Transfer NaCl in a clean 1 L volumetric flask using a funnel.
3. Wash the funnel with 0,9 L demineralized water.
4. Put the flask in a thermostat and maintain 30 min at 20 0C.
5. Add demineralized water up to the mark.
6. Stir vigorously and transfer in a clean bottle with stopper.
7. Add a label with necessary information.
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How do you prepare a 500mL of 1M of NaCl solutuion?
If you need to make just 100mL, then you need 1 tenth of a liter that is 5M. If you were to make 1L of 5 molar NaCl, you would need 5 times the molar mass of NaCl (58.44g/mol) dissolved in 1L of water. Thus for 1L of a 5M solution you need 5 * 58.44g, or 292.2 grams of NaCl. However, since we only want 100mL, which is 1/10 of a Liter, we also only need 1/10 the amount of NaCl, or 292.2 / 10, which is 29.22g. So, measure out 29.22g NaCl, and dissolve completly in a volume less than 100mL, say 80mL, then bring the final volume up to 100mL. You now have 100mL of a 5M NaCl solution.
How would you prepare 30mL of a 5M NaCl solution from a 2M NaCl stock solution?
You have to evaporate (by open boiling) 45 mL of the 75 mL 2M NaCl solution thus reducing the volume to 30 mL 5M NaCl.
What Volume of 5M HCl to make tris buffer at pH 7.5?
To make a Tris buffer at pH 7.5, you will need to mix Tris base with HCl. To calculate the volume of 5M HCl needed, you will first need to determine the molarity of the Tris buffer solution and then use the Henderson-Hasselbalch equation. The exact volume of 5M HCl required will depend on the amount of Tris base used and the final volume of the buffer solution.
A sample of 76g of NaCl is dissolved to make 1L of solution. what is the molarity of the solution?
1.3g
What volume of 2.85M NaCl solution contains .400 mol NaCl?
0,4 mol NaCl is 23,376 g.2,85 mol NaCl is 166,554 g to 1L.140 mL solution NaCl 2,85 M contain 0,4 mol NaCl.
What is gram percent?
Gram percent is the number of grams of a solute per 100 grams of a solution. For example, if a solution of NaCl and water was said to have a 0.02g% of NaCl, this would mean that for 100g of saline solution, 0.02 of those grams are salt. Since 1L of water weighs 1kg (at normal conditions), there would be .2g of NaCl in 1L of a 0.02g% NaCl solution.
How many moles of NaCl is required to make 1L of a 140mM solution?
To find the moles of NaCl needed, first convert 140 mM to M by dividing by 1000. Then, use the formula moles = Molarity x Volume (in liters) to calculate the moles required. In this case, the calculation would be: 0.140 mol/L x 1 L = 0.140 moles of NaCl.
How many grams of NaCl would you use to make 100ml of a 4M solution?
The Molecular Weight of NaCl = 58.5 So to make 1L of 4M NaCl solution you need 4*58.5=234g of NaCl So to make 100mL of the above solution you need 23.4 grams of NaCl
Calculate the volume of a cylinder with a radius of 3m and a depth of 5m?
V = 141.37 m3
How do you calculate the concentration of two mixed solutions?
calculate final molarity of the solution if 11ml of 5m solution is made up to 20ml
How do you calculate the maximum bending moment for a light 5m beam carrying a uniformly distributed load of 38kN?
w(l^2)/8 w = 38N l = 5m
How to calculate NaCl density?
The density can be measured experimentally.
