25 gallons
25% of 10 gallons = 2.5 gallons
25 percent of 10 gallons is 2.5 gallons.
25% of 20 = 20*25/100 = 5
25
6.40 because if you can find 25 percent and 5 percent you can take 5 percent from 25 percent for 20 percent.
The question is best solved using basic algebra. You need 20 gallons of 32% alcohol. This will contain 0.32*20 = 6.4 gallons of pure alcohol. Now suppose you have X gallons of 25% alcohol in the mixture. That contains 0.25X gallons of pure alcohol. Also, since you have 20 gallons in total, you must have 20-X gallons of the 35% alcohol. This will contain 0.35*(20-X) = 7 - 0.35X gallons of pure alcohol. Then, the total amount of pure alcohol is 0.25X + 7 - 0.35X = 7 - 0.1X gallons. So you have 7 - 0.1X = 6.4 or 0.6 = 0.1X or X = 6. So the answer is 6 gallons of 25% alcohol and 14 gallons of the stronger stuff!
2.5 gallons
7.5 gallons
20
80 percent of 25 is 20.
25% of 80 = 80*(25/100) = 20