2
Yes but a bit more. Difference is subtract and then take the absolute value. The difference between 5 and 9 is not 5 - 9 = -4, but abs(5 - 9) = abs(-4) = 4 Thus, the difference between 5 and 9 is the same as the difference between 9 and 5.
abs(x-33) or |x-33|
No difference ABS, Antilock Braking System.
It is abs(5 - 2n) = 1
Abs(9 - n)
An abs rotor could be heavier duty, and could have a tone ring for a speed sensor to read off of.
is 10*abs(d-3) or 10*|d-3| where abs is the absolute difference between d and 3 ie it is always the positive value.
The difference between the fractions a/b and c/d = abs[(ad - bc)/bd]
Abs(n - 8) = 22
The Rock
The difference is abs{(-3) - 5} = abs{-3 - 5} = abs{-8} = 8