whether we know that p-n diode is real diode. But still in case of semeconductor we see then silics is real diode.
If it is a light emitting diode it is there to let you know that the relay is energized. In my experience, when a DC current is removed from a coil, the polarity of the magnetic field reverses and if it weren't for the diode, the relay would "chatter". The diode polarity is oppsite of the actuating voltage.
peak inverse voltage... piv of semiconductor is impoetant bcz we need to know after a peak voltage the diode get breakdown or damaged... so we need to know the peak voltage. piv is a point which withstands the maximum reverse biased voltage. after which the diode get damaged.
A: If you know the total resistance and total voltage then you know total current flow for the circuit, this current will be same for every resistor in series however the voltage drop will change for each resistor . So measuring the voltage drop across the resistor in question and divide by the total current will give you the resistor value.
Resistance is used in characterizing silicon diodes, or any component for that matter, because the equivalent resistance in a certain condition tells you what the circuit will do in that condition. It is true that a diode is not a resistor, but it has an equivalent resistance at each point on it operating curve. Let take three points, for example... With one ampere of current, the forward voltage might be 0.68 volts. That corresponds, using Ohm's law, to a resistance of 0.68 ohms. With ten amperes of current, the forward voltage might be 1.15 volts. That corresponds to a resistance of 0.115 ohms. With 25 amperes of current, the forward voltage might be 1.7 voltage. That corresponds to a resistance of 0.068 ohms. You can obtain the forward resistance curve from the manufacturer's data sheet. Even if there is only a voltage versus current curve, you can calculate resistance using Ohm's law. You need to know the resistance curve in order to design the circuit that uses the diode. In high performance situations, such as in large power supplies, the resistance of the diode may well be critical, and would therefore be a factor in selecting which diode amongst several choices to choose.
Any of these: Voltmeter: Across the Resistor, Vmax when diode conducts, 0 when you switch polarity Across the diode Vmin when conducting, Vmax when not. Ammeter: in series with ckt, Amax when conducting Amin when not, etc. Ohmmeter: No power required. Lo R one way, Hi R when leads reversed
You can test it by puting it in forward bias with a resistor. Use a dc voltage source of 5 volts and put it in series with 250 Ohms resistor. Or use 9volts with a 450 Ohms resistor. Basically you need 20mA of forward current usually. Smaller current will reduce brightness.
Patience and know things about electricity
whether we know that p-n diode is real diode. But still in case of semeconductor we see then silics is real diode.
To determine the value of the resistor needed, you would typically need to know the voltage across the resistor and the desired current flowing through it. The value can be calculated using Ohm's Law: resistance (in ohms) = voltage (in volts) / current (in amperes).
It should be marked, either on the diode or on the box it came in. If you can't find the mark, then you have to measure it yourself. Take the zener diode, a battery or DC power supply, and a resistor. Wire them all in series, with the NEG (cathode) end of the diode closer to the POSitive side of the battery or power supply. Connect your voltmeter across the diode, and slowlyincrease the power supply output voltage while watching the meter. You'll see the voltage across the diode increase slowly, tracking the power supply, until you reach the Zener voltage. At that point, the voltage across the diode won't increase any more; it'll just stay there at its 'reverse breakdown' voltage, which is the Zener voltage. (If the voltage across the diode goes to around a volt and won't go any higher, the polarity is wrong. Reverse either the diode or else the power supply.) You probably want a wild guess at what the value of the resistor should be. That's difficult to specify if I don't know the power rating of the Zener diode you're testing. I'm going to make the following suggestion completely in the blind: Select the resistor to limit the series current to 30 mA even if you have to crank the power supply up to 50 volts. R = 50/.03 = 1.5 to 2 K-ohms, rated for a couple of watts.
If it is a light emitting diode it is there to let you know that the relay is energized. In my experience, when a DC current is removed from a coil, the polarity of the magnetic field reverses and if it weren't for the diode, the relay would "chatter". The diode polarity is oppsite of the actuating voltage.
A malfunctioning blower motor resistor will cause the blower motor not to work. When the resistor is bad the blower motors will not turn on.
yes it can. i cant believe you didn't know that.
A diode is unidirectional because of the diode only conduct in forwardbias .As you know the diode have two terminal cathode and anode . and when the positive terminal of battery connected to the p-side and other terminal connected to the other terminal of diode then diode is called forward biased . and when it connection is just opposite then it become in reverse biased . so we can finally say that the diode is unidirectional
peak inverse voltage... piv of semiconductor is impoetant bcz we need to know after a peak voltage the diode get breakdown or damaged... so we need to know the peak voltage. piv is a point which withstands the maximum reverse biased voltage. after which the diode get damaged.
You can only use a resistor to drop a voltage at a constant current. If you know the current, use Ohm's law to calculate the resistor value.