Wiki User
∙ 14y agoYour sentence structure makes this question virtually incomprehensible. But if I am understanding correctly, it is most likely the overload relay is tripping on inrush when the motor is initially turned on, or the motor could be locked up, causing it to pull too much current in an attempt to reach normal operating RPMs. I'd examine the motor, and make sure it is working correctly and clean.
Wiki User
∙ 14y agoIt is a type of starter that allows a motor to be started across the line by starting the motor with a reduced inrush current. The motor is started in a wye configuration until it gets up to speed and then a timer drops the wye contactor out a draws the delta configured contactor in. The motor then operates in a delta wired configuration.
Full load current ofthe motor x 0.58
THE FIRST THING IS TAKE THE READING OFF LOAD AND SEE IF THEY ARE BALANCED. HAS THE MOTOR BEEN RECENTLY REWOUND? GET A MOTOR REPAIR COMPANY TO LOOK AT THE MOTOR AND SEE IF IT HAS BEEN WOUND CORRECTLY. IF THE STAR-DELTA WORKS CORRECTLY IT SHOULD START IN STAR FOR ABOUT FIVE TO TEN SECONDS AND GO INTO DELTA THIS IS DEPENDANT ON THE STARTING CURRENT THE MANUFACTURE OF THE SWITCH AND THE APPLICATION. CHECK ALL THREE PHASES ARE BALANCED AND IF THEY ARE THE MOTOR WINDINGS MAY NOT BE CORRECTLY WOUND. SOME HAVE STAR CONNECTIONS BUILT IN.LOOKING AT THE AMPERAGE THE LOAD REQUIREMENT IS ONLY A FRACTION OF WHAT YOU ARE GETTING SO IT LEAVES ONLY TWO THINGS I......MOTOR FAULT 2.....WHAT EVER THE MOTOR IS DRIVING IS PUTTING A MASSIVE PRESSURE ON THE MOTOR CAUSING IT TO OVERLOAD.
If a motor 3 phase or single phase goes above the full load amps that is on the nameplate of the motor then it is in overload condition. This is usually caused by trying to drive machinery with less horsepower that the manufacturer recommends To protect the motor from this condition overload heaters are put in series with the supply voltage and the motor leads. If the current from the motor draws more that the motor's nameplate FLA then the overload heater opens the supply voltage through use of a motor contactor. The contactor can not be closed again until the motor overload heaters cool down and by the same token the motor gets a chance to cool down. This condition is rectified by either using a bigger HP rated motor or lowering the load on the machinery that the motor is driving.
If the motor is connected to an ungrounded delta supply service there will be no effect on the operation of the motor. If the motor is connected to a wye system supply service and the B phase grounds out, the motor's overload protection would take the motor off line from the electrical supply.
On a star delta starter a motor overload or a motor going to ground and cause a short circuit will cause the overload protection to trip. These overloads have to be reset before the motor can be restarted.
by adding a capacitor on the start winding
It is a type of starter that allows a motor to be started across the line by starting the motor with a reduced inrush current. The motor is started in a wye configuration until it gets up to speed and then a timer drops the wye contactor out a draws the delta configured contactor in. The motor then operates in a delta wired configuration.
Full load current ofthe motor x 0.58
THE FIRST THING IS TAKE THE READING OFF LOAD AND SEE IF THEY ARE BALANCED. HAS THE MOTOR BEEN RECENTLY REWOUND? GET A MOTOR REPAIR COMPANY TO LOOK AT THE MOTOR AND SEE IF IT HAS BEEN WOUND CORRECTLY. IF THE STAR-DELTA WORKS CORRECTLY IT SHOULD START IN STAR FOR ABOUT FIVE TO TEN SECONDS AND GO INTO DELTA THIS IS DEPENDANT ON THE STARTING CURRENT THE MANUFACTURE OF THE SWITCH AND THE APPLICATION. CHECK ALL THREE PHASES ARE BALANCED AND IF THEY ARE THE MOTOR WINDINGS MAY NOT BE CORRECTLY WOUND. SOME HAVE STAR CONNECTIONS BUILT IN.LOOKING AT THE AMPERAGE THE LOAD REQUIREMENT IS ONLY A FRACTION OF WHAT YOU ARE GETTING SO IT LEAVES ONLY TWO THINGS I......MOTOR FAULT 2.....WHAT EVER THE MOTOR IS DRIVING IS PUTTING A MASSIVE PRESSURE ON THE MOTOR CAUSING IT TO OVERLOAD.
If a motor 3 phase or single phase goes above the full load amps that is on the nameplate of the motor then it is in overload condition. This is usually caused by trying to drive machinery with less horsepower that the manufacturer recommends To protect the motor from this condition overload heaters are put in series with the supply voltage and the motor leads. If the current from the motor draws more that the motor's nameplate FLA then the overload heater opens the supply voltage through use of a motor contactor. The contactor can not be closed again until the motor overload heaters cool down and by the same token the motor gets a chance to cool down. This condition is rectified by either using a bigger HP rated motor or lowering the load on the machinery that the motor is driving.
A device with an overload protection used to control a motor is an Overload Relay.
according motor which we use suppose if it is 2.2kw then the range of OLR(over load relay) is 2-3.2
If the motor is connected to an ungrounded delta supply service there will be no effect on the operation of the motor. If the motor is connected to a wye system supply service and the B phase grounds out, the motor's overload protection would take the motor off line from the electrical supply.
overload heater is used to protect a large electric motor. If the overload heater get too hot from excessive current. its nomally-closed overload contacts wil open. interruptting the circiut of powe supply of motor
It won't. Star and Delta deliver the exact same power. The only difference is Star (also called wye) configurations contain a neutral and allow single-phase, ground referenced loads to be fed. also star wiring draws less current when the motor starts up, but is less efficient when motor is at running speed so it is then switched over in to delta mode as that draws less current in runing mode
A breaker is based on the amount of current that the motor draws. This amperage should be taken off of the motors nameplate. In motors of a specific horsepower the amperage is proportional to the voltage the motor uses. Without the motors voltage this question can not be answered.