A typical resistor will burn out when it dissipates power in excess of double its power dissipation rating for an extended period of time. The power dissipated by a resistor is equal to I2R or E2/R, where E = the voltage across the resistor I = the current through the resistor R = the resistance of the resistor
A: That refers to a resistor pull up that is not sufficient to do the job that is to pull up. It also means is greater in value that it should be
Connecting an ammeter in parallel subjects that ammeter to the full supply voltage. The shunt resistor is not designed to sustain that value of voltage and will burn out. Also, the clue is in the word 'shunt' (which means 'in parallel') which means that the coil will also burn out!
Normally if a resistor fails they will either increase in value or open up at all (open circuit).
Resistors are rated in wattage so the lowest wattage rating will be the wattage of the series circuit. It will be able to handle that power any more and the lowest wattage resistor could be damaged and fail.Another AnswerWhen two or more resistors are connected in series, the resistor with the lowest resistance will operate at the highest power. If the power developed by a resistor exceeds its rated power, then the resistor may burn out.
A typical resistor will burn out when it dissipates power in excess of double its power dissipation rating for an extended period of time. The power dissipated by a resistor is equal to I2R or E2/R, where E = the voltage across the resistor I = the current through the resistor R = the resistance of the resistor
A "pull-up" resistor is a resistor used to to perform a specific electronic function - it is not a different type of resistor. A very small current flows through a pull-up resistor so it does not need to be high wattage (1/8 watt is generally fine). The value of a pull-up resistor depends on the resistance of the sensor. If it is simply on or off (no resistance) then a typical pull-up resistor might be 10k ohms.
This depends on the type of resistor. Carbon composition and metal film resistors typically will burn open, carbon film types can short.
Because if you dont you will burn and might get athsma Because if you dont you will burn and might get athsma Because if you dont you will burn and might get athsma
The old resistor was burned out. If you burn out the new one again, replace the blower motor.
A resistor may burn out due to excessive power dissipation, which can be predicted by calculating the power across the resistor using P = I^2 * R or P = V^2 / R, where P is power, I is current, V is voltage, and R is resistance. If the calculated power exceeds the resistor's power rating, it is likely to burn out. Additionally, factors like ambient temperature, resistor material, and external stresses should also be considered in predicting resistor burnout.
Current moving through a resistor causes it to heat up because of the flowing electrons bumping into the atoms in the resistor.
Yes it can. If there is a bad wire in your harness the ballast resistor will get hot, in which causes your coil to overheat and cut out or burn outline.
A: That refers to a resistor pull up that is not sufficient to do the job that is to pull up. It also means is greater in value that it should be
A potentiometer.
Connecting an ammeter in parallel subjects that ammeter to the full supply voltage. The shunt resistor is not designed to sustain that value of voltage and will burn out. Also, the clue is in the word 'shunt' (which means 'in parallel') which means that the coil will also burn out!
If it's a fan speed issue check the blower motor resistor & the blower motor. Check the plugs at the resistor and blower motor for burn marks also.