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Q: Why does an array always start with index 0?
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How do you start array list from 1?

Array indices are zero-based because the first element is at offset zero from the start of the array. There is no such thing as a one-based array in C. Some other languages do allow you to specify the base of an array, but converting a non-zero-based index to a zero-based index adds a runtime overhead to the implementation.


Why array indexes starts from zero in c-language?

In order to provide modulo (%) facilities as far as mathematics and logic is concern. for instance , if we have no of employees in our list say 1545 and if we want to accommodate it within small and effective range then by using % we can do it easily.... we can arrange it in the range within Array with maximum index 14 (0,1,2,.....14). And 0,15,30,45......1545 will belongs to same category say index no 0. Think if 0 is not included into index then where we would store 0,15,30,45....1530,1545 . From a technical standpoint, you need to understand that an array is basically just the starting address of a chunk of memory. The "index" of the array is actually an address offset. So the value at the 0th position would be stored at the address of the array plus zero. The value at the 1st position would be stored at the address plus one, and so on.


What is the default index of an array's first position in most languages?

0


Full defecation of array?

Full representation of an array begins from the index 0 and ends at n-1 where n is the number of variables of the array.


Why the index of an array be a positive number?

Since an array cannot contain a negative number of items, the size of an array must be at least 0. So if you ever tried to retrieve the element at a negative index in an array, it would automatically be understood to be out-of-bounds.