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If we use 7 binary digits (Computers counting systems is binary) we end up with 127. That isn't enough to hold all the characters. So we make it 8 binary digits. The maximum number for 8 binary digits is 11111111. Which in our counting system is 255.
AnswerASCII is a 7-bit character encoding, so it has only 128 codes: 0 through 127. The upper 128 codes in an 8-bit byte (128 through 255) are unused and undefined by ASCII, but many ASCII extensions (such us ISO-8859-1) make use of those unused codes.
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Ezra8-bit is enough to contain all alpha numeric characters in English and then some (control characters) , so going larger than 8 was pointless.
Today stuff like UTF-8 need to have more than 8 bits a char as it has a huge number of characters and symbols as it supports a ton of spoken languages and symbols
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How many bit are used to encode an ASCII character?
All ASCII character sets have exactly 128 characters, thus only 7-bits are required to represent each character as an integer in the range 0 to 127 (0x00 to 0x7F). If additional bits are available (most systems use at least an 8-bit byte), all the high-order bits must be zeroed. ANSI is similar to ASCII but uses 8-bit encodings rather than 7-bit encodings. If bit-7 (the high-order bit of an 8-bit byte) is not set (0), the 8-bit encoding typically represents one of the 128 standard ASCII character codes (0-127). If set (1), it represents a character from the extended ASCII character set (128-255). To ensure correct interpretation of the encodings, most ANSI code pages are standardised to include the standard ASCII character set, however the extended character set depends upon which ANSI code page was active during encoding and the same code page must be used during decoding. ANSI typically caters for US/UK-English characters (using ASCII) along with foreign language support, mostly European (Spanish, German, French, Italian). Languages which require more characters than can be provided by ANSI alone must use a multi-byte encoding, such as fixed-width UNICODE or variable-width UTF-8. However, these encodings are standardised such that the first 128 characters (the standard ASCII character set) have the same 7-bit representation (with all high-order bits zeroed).
How many bits are required to store AR in computer memory?
In ASCII code, each letter, number or punctuation mark takes one byte, or 8 bits. That gives you 256 discrete combinations. Two letters take 2 bytes, or 16 bits.
What is the difference between ascii and ebcdic?
Due to the advancement of technology and our use of computers, the importance of ASCII and EBCDIC have all but ebbed. Both were important in the process of language encoding, however ASCII used 7 bits to encode characters before being extended where EBCDIC used 8 bits for that same process. ASCII has more characters than its counterpart and its ordering of letters is linear. EBCDIC is not. There are different versions of ASCII and despite this, most are compatible to one another; due to IBMs exclusive monopolization of EBCDIC, this encoding cannot meet the standards of modern day encoding schemes, like Unicode.
Why calculating with cheat engine is always X 8?
This is because the byte values ​​are converted into bits. because you can only work with bits....
Where does negative ASCII value used?
There is no such thing as a negative ASCII value. ASCII values are always in the range 0-255. In C++, a char is defined as an unsigned integer of 8-bits in length (wide chars are unsigned integers of 16-bit length). Since they are unsigned, they can never be negative. C differs from C++ in that a C char is generally represented as a signed integer (typically 32-bits on a 32-bit system). However, when cast as a character, only the low-order byte is used, which effectively ignores the sign in the high-order byte. In other words, the absolute value is used, regardless of the sign. The same applies to wide characters.
