Wiki User
∙ 14y agothe modulation system is of FM
Wiki User
∙ 14y ago1200/sqrt(2) = 848.5 (rounded)
For to keep the resonant frequancy constant L*C has to stay same. Lets say if you double L you have to divide C by 2 to keep the same resonant frequency. If only L increases Resonant frequency decrease, this is same for C.
It is halved. coz voltage=current * resistance
DATE: 17-MAY-12 THE CAPACITIVE REACTANCE VARIES INVERSELY WITH THE AMOUNT OF THE PRODUCT OF MAGNITUDE OF THE SUPPLY FREQUENCY, TWICE THE VALUE OF CONSTANT PI AND THE MAGNITUDE OF CAPACITANCE. IN OTHER WORDS, EVERY TIME YOU INCREASE ANY OF THESE FACTORS OR IF SAY YOU FIX THE VALUE OF CAPACITANCE TO SAY 1 MICROFARAD AND OTHER FACTOR (i.e. 2 x PI) AS CONSTANT ALSO, BUT THEN WHEN DOUBLING THE FREQUENCY, SO THEN THE EFFECT TO THE CAPACITIVE REACTANCE WILL BE INVERSELY OR HALVED. THE MORE YOU INCREASE THE FREQUENCY, THE SMALLER THIS VALUE WILL BE. WHICH IN EFFECT ALLOWING MORE HIGH FREQUENCY CURRENT OR VOLTAGE TO PASS THRU THE CIRCUIT. AND THE REVERSE IS TRUE, MEANING ONCE YOU ALLOW LOW FREQUENCY CURRENT, THEN THE CAPAICTIVE REACTANCE WILL INCREASE AS A RESULT. BY FMSJr. / ABU DHABI, UAE
The current in the circuit will be decreased by half. Ohm's law states V=IR so, I=V/R. If R is doubled, then I= V/2R.
It's Angle modulated system where the amplitude remains constant & frequency & phase varies with respect to modulating signal.
IF a wave moving at a constant speed were to have it's wavelength doubled (Wavelength x 2), then the frequency of the wave would be half of what it originally was (Frequency / 2).
If the amplitude of a wave is doubled while the frequency remains constant, the speed of the wave will not change. The speed of a wave is determined by the medium through which it is traveling, not by its amplitude or frequency.
When the frequency of a wave is doubled, the wavelength is halved. This is because the speed of a wave is constant in a given medium, so an increase in frequency results in a decrease in wavelength to maintain a constant speed.
If the frequency of a wave traveling in a rope is doubled, the speed of the wave will remain the same. The speed of a wave in a medium is determined by the properties of the medium, not by the frequency of the wave.
If the frequency is doubled, the wavelength of the wave will be halved. This is because the speed of the wave remains constant, so as frequency increases, the wavelength decreases to maintain that constant speed.
More than doubled. The stopping voltage is the photon energy minus the work function: hv - W Doubling the photon energy creates a new stopping voltage of: 2 hv - W > 2 (hv - W)
If the frequency is doubled, the wavelength is halved. This is because the speed of the wave remains constant, as determined by the medium it is traveling through. The wavelength and frequency of a wave are inversely related according to the equation: speed = frequency x wavelength.
Frequency = Velocity divided by wavelength. So if frequency is doubled that means velocity is doubled but the wavelength is halved. You can see this by keeping wavelength a constant : If Frequency =1 and Wavelength= 1 1= Velocity/1 Velocity=1 If Frequency =2 and Wavelength= 1 2= Velocity/1 Velocity =2 OR keeping Velocity constant: If Frequency =1 and Velocity= 1 1= 1/Wavelength Wavelength =1 If Frequency =2 and Velocity= 1 2= 1/Wavelength Wavelength=1/2
If the frequency of a wave is doubled while the wave speed remains constant, the wavelength of the wave will be halved. This is because wavelength and frequency are inversely proportional in a wave, so when one doubles, the other is halved to keep the wave speed constant.
If the amplitude of a system in simple harmonic motion is doubled, the frequency of the oscillation remains unchanged. Frequency is determined by the system's mass and the spring constant, and increasing the amplitude does not affect these factors.
The frequency is the reciprocal of the period. If the period is doubled, the frequency will change by a factor of 1/2.