Inside the circuit loop between the inductor and capacitor the current will be at maximum. Outside the circuit the current through the LC tank circuit will be at minimum. It depends on where you are measuring it.
The current is 0. Current is the unit of flow of electrons in a circuit, and in an open circuit, electrons cannot flow. Therefore there is 0 current. Another way to look at it is that I = V / R, where I = Amps (current), V = voltage, and R = resistance (impedance). In an open circuit, the impedance is infinite, and by using our math skills, we know that X (or V in our case) divided by infinity, is 0. I = V / Infinity = 0
It depends of your panel ratings. usualy, a panel short-circuited has a maximum current, you can base the value on that. But if you are doing an array of panels, you have to pai attention to the parallel connection, once that multiplies the current across the circuit. in this case you have to use diodes that support the current of the array.
The base-emitter voltage of a BJT is dependent on temperature and current. The minimum voltage ranges from 0.6V to 0.7V. Anything less, and the transistor goes into cutoff. As far as "proper voltage" is concerned, it is more correct to say "proper current", because that is the basis for the BJT - it is a current amplifier, not a voltage amplifier. The proper current depends on the particular biasing design of the circuit at hand.
IN A SERIES RLC CIRCUIT XL=XC.THEREFORE, IMPEDANCE Z IS MINIMUM AND Z=R.SINCE THE IMPEDANCE IS MINIMUM,CURRENT IN THE CIRCUIT WILL BE MAXIMUM. XL=XC MULTIPLYING BY MAX. CURRENT Io (AT RESONANCE) ON BOTH SIDES, WE GET, IoXL=IoXC I.E. Vlo=Vlc(POTENTIAL DIFFERENCE ACROSS INDUCTANCE IS EQUAL TO THE POTENTIAL DIFFERENCE ACROSS CAPACITANCE AND BEING EQUAL AND OPPOSITE THEY CANCEL EACH OTHER.)SINCE Io IS MAXIMUM,Vlo AND Vco WILL ALSO BE MAXIMUM.THUS,VOLTAGE MAGNIFICATION TAKES PLACE DURING RESONANCE.HENCE,IT IS ALSO REFERRED TO AS VOLTAGE MAGNIFICATION CIRCUIT.
Inside the circuit loop between the inductor and capacitor the current will be at maximum. Outside the circuit the current through the LC tank circuit will be at minimum. It depends on where you are measuring it.
For a particular frequency if the current or the voltage of the circuit is Maximum or Minimum then that circuit is said to be in resonance .
In a parallel circuit, each branch has its own current path, allowing the total current to be the sum of the currents in each branch. This is why it is known as current magnification. However, at resonance, the impedance in the circuit is at its minimum, causing the total current in the circuit to decrease. This does not change the fact that individual branches can still have higher currents than in a series circuit due to the unique current paths in a parallel arrangement.
No current bro? Depends
30 m amp
Minimum circuit ampacity is the smallest current carrying capacity required for an electrical circuit to safely handle the load connected to it. It is determined by factors such as the type of equipment being used, ambient temperature, and the wiring insulation. The minimum circuit ampacity helps ensure that the circuit can supply enough power without overheating or causing a fire hazard.
In an L-C-R AC series circuit, resonance occurs when the capacitive and inductive reactances cancel each other out, resulting in minimum impedance. This causes the current in the circuit to be at its maximum and the power factor to be unity. By measuring the frequency at which resonance occurs, one can determine the values of the inductor, capacitor, and resistor in the circuit.
The accuracy of ammeter changes as the resistance is increased or decreased.AnswerThe simple answer is yes, it will change. However, whether it will be a perceptible change is another question. Ammeters are designed to cause the minimum change to the actual circuit current when they are inserted into a circuit.
The current is 0. Current is the unit of flow of electrons in a circuit, and in an open circuit, electrons cannot flow. Therefore there is 0 current. Another way to look at it is that I = V / R, where I = Amps (current), V = voltage, and R = resistance (impedance). In an open circuit, the impedance is infinite, and by using our math skills, we know that X (or V in our case) divided by infinity, is 0. I = V / Infinity = 0
threshold
(mA of current the circuit draws from the battery when it's running) multiplied by (number of hours you want the circuit to operate from the battery) is equal to the absolute minimum mAh rating the battery must have.
Latching current is the minimum amount of current required to maintain the thyristor in on-state immediately after a thyristor is turned on..and Holding current is a minimum current that is required to maintain the thyristor in on-state not allowing it to turn off.Alternative AnswerIf you are referring to a relay or contactor, when the relay is de-energised, there is a break in the magnetic circuit, so the magnetic circuit has an airgap which makes it have a high reluctance. When the relay is energised, the magnetic circuit causes the armature to close, removing the airgap and reducing the value of reluctance. So, when you first energise the relay, there must be a greater magnetomotive to overcome the higher reluctance. When the relay is closed, a lower magnetomotive force will be sufficient to overcome the lower reluctance and maintain the relay closed.