30 mAmp rating devices are commercially available.
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Inside the circuit loop between the inductor and capacitor the current will be at maximum. Outside the circuit the current through the LC tank circuit will be at minimum. It depends on where you are measuring it.
The current is 0. Current is the unit of flow of electrons in a circuit, and in an open circuit, electrons cannot flow. Therefore there is 0 current. Another way to look at it is that I = V / R, where I = Amps (current), V = voltage, and R = resistance (impedance). In an open circuit, the impedance is infinite, and by using our math skills, we know that X (or V in our case) divided by infinity, is 0. I = V / Infinity = 0
It depends of your panel ratings. usualy, a panel short-circuited has a maximum current, you can base the value on that. But if you are doing an array of panels, you have to pai attention to the parallel connection, once that multiplies the current across the circuit. in this case you have to use diodes that support the current of the array.
The base-emitter voltage of a BJT is dependent on temperature and current. The minimum voltage ranges from 0.6V to 0.7V. Anything less, and the transistor goes into cutoff. As far as "proper voltage" is concerned, it is more correct to say "proper current", because that is the basis for the BJT - it is a current amplifier, not a voltage amplifier. The proper current depends on the particular biasing design of the circuit at hand.
IN A SERIES RLC CIRCUIT XL=XC.THEREFORE, IMPEDANCE Z IS MINIMUM AND Z=R.SINCE THE IMPEDANCE IS MINIMUM,CURRENT IN THE CIRCUIT WILL BE MAXIMUM. XL=XC MULTIPLYING BY MAX. CURRENT Io (AT RESONANCE) ON BOTH SIDES, WE GET, IoXL=IoXC I.E. Vlo=Vlc(POTENTIAL DIFFERENCE ACROSS INDUCTANCE IS EQUAL TO THE POTENTIAL DIFFERENCE ACROSS CAPACITANCE AND BEING EQUAL AND OPPOSITE THEY CANCEL EACH OTHER.)SINCE Io IS MAXIMUM,Vlo AND Vco WILL ALSO BE MAXIMUM.THUS,VOLTAGE MAGNIFICATION TAKES PLACE DURING RESONANCE.HENCE,IT IS ALSO REFERRED TO AS VOLTAGE MAGNIFICATION CIRCUIT.