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∙ 13y agoThe RMS current for an 8.0 µF capacitor attached to a 120 V rms 60 Hz source is 39,798 amperes.
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∙ 13y agoSince they're connected in parallel directly across the source, the voltages across both componentsare equal, and are equal to the source, i.e. 120 v DC.
120 volts X 13 amps is 1560 watts.
V = I x R so 120/96.8 = 1.24 Amps.
A: absolutely not lamps needs current a long cord introduce IXR drop making less current for the lamp to use it
It is not clear what exactly is being asked-for in this question. If it could be asked again, with a bit more detail as to what part of a household 110-120 Volt circuit is required, someone may be able to give a better answer than this one.
Yes. Voltage is shifted 120 degrees.
Since they're connected in parallel directly across the source, the voltages across both componentsare equal, and are equal to the source, i.e. 120 v DC.
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120 volts X 13 amps is 1560 watts.
The direction of the current refers to the flow of electric charge. In a circuit, current flows from the positive terminal of the voltage source to the negative terminal, opposite to the direction of electron flow.
V = I x R so 120/96.8 = 1.24 Amps.
No, it is not safe to use a 120-volt start capacitor on a 220-volt motor. The capacitor voltage rating must match or exceed the motor's operating voltage to prevent damage to the motor and ensure safe operation. It is important to use the correct voltage-rated capacitor for the motor to avoid potential hazards.
To find the current flowing through the microwave, you can use the formula: Power (P) = Voltage (V) x Current (I). Given the power is 1200 W and voltage is 120 V, you can rearrange the formula to solve for current: I = P / V. Therefore, I = 1200 W / 120 V = 10 A. The current flowing through the microwave is 10 amps.
R = E / I = 120/2 = 60 ohms.
temporary it blows or KABOOOMM....
The apparent answer to the question would be (100 W)/(120 V) = 0.8333 A, assuming that, as a pure resistance load, the light bulb has a power factor close to 1.0.