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Mov ax,data mov ds,ax mov dl,05h up2: lea si,ser1 mov cl,05h up1: mov al,ds:[si] mov ah,al inc si cmp al,ds:[si] jc down mov ah,ds:[si] mov ds:[si],al dec si mov ds:[si],ah inc si down:dec cl jnz up1 dec dl jnz up2 int 3h
; program for moving a string from one block of memory ;to another block of memory data segment str1 db 'suriya',0 str2 db 20 dup(0) data ends code segment assume cs:code,ds:data,es:data start: mov ax,data mov ds,ax mov es,ax mov cx,6 lea si,str1 lea di,str2 cld rep movsb int 3h code ends end start
data segment strs db 'madam',0 strr db 5 dup(0) data ends code segment assume cs:code,ds:data,es:data start:mov ax,data mov ds,ax mov es,ax mov cx,6 lea si,strs lea di,strr l1:mov al,strs[si] mov strr[di],al inc si dec di loop l1 mov cx,6 repe cmpsb jz l3 mov bx,0000h jmp l4 l3:mov bx,1111h l4:int 3h code ends end start
simplify both sides of the equation: 1/3h+(-4)(2/3h)+(-4)(-3)=2/3h+-6 ~ distribute that 1/3h+-8/3h+12=2/3h+-6 (1/3h+-8/3h)+(12)=2/3h-6 ~ combine like terms for this -7/3h+12=2/3h-6 -7/3h+12=2/3h-6 subtract 2/3h from both sides: -7/3h+12-_2/3h=_2/3h-6-2/3h -3h+12=6 subtract 12 from both sides: -3h+12-12=-6-12 -3h=-18 divide both sides by -3 -3h/-3=-18/-3 h=6
3h+13 = 7 3h = 7-13 3h = -6 h = -2
h = -5 8h - 10h = 3h + 25 -2h = 3h + 25 -2h - 3h = 3h - 3h + 25 -5h = 25 h = -5 CHECK: 8(-5) - 10(-5) = 3(-5) + 25 -40 - -50 = -15 + 25 -40 + 50 = 10 10 = 10 CORRECT
8h - 10h = 3h + 25-2h = 3h + 25-5h = 25-h = 5h = -5
3h + 20 - h + 5 = 2h + 25
- 3h - 2h + 6h + 9 = h + 9
The value of 4g - 3h can't be determined since we are not given the value of g and h. The value of 4g - 3h is actually itself without the known values for g and h.
Monday-morning 2h evening 3h Tuesday-3h 2h Wednsday-1/2h 3/2h thursday-3h 2h Friday-2h 3h Saturday-3h 3h She would usually do alot of sprinting leading up to the games and she would do alot of technique to make her swim faster. She is a very competitive swimmer with alot of courage for her and her teammate's. She has a good hart and one day i would really like to meet her.
-9h-6+12h+40 = 22 3h+34 = 22 3h = 22-34 3h = -12 h = -4
5h - 3h + 9h = 176 11h = 176 h = 16
3h
Pr(3H given >= 2H) = Pr(3H and >= 2H)/Pr(>=2H) = Pr(3H)/Pr(>=2H) = (1/4)/(11/16) = 4/11.