It really does depend upon what you mean by 'shift'. For purely-resistive circuits, the load current is in phase with the supply voltage. For reactive circuits, the load current will lead or lag the supply voltage; for capacitive-resistive circuits, the load current leads, whereas for inductive-resistive circuit, the load current lags. You can change the angle by which the current leads or lags (the 'phase angle') by changing the amount of resistance or reactance.
For instance, there is the difference between -direct current- and -alternate current- For example: a simple battery gives direct current, e bicycle-dynamo generates alternate-current, so plus becomes minus and vice versa several times a second. A symbol for direct current can be: ____ - - - A symbol for alternate current is a small sine-wave: ~
By a current pump you might mean an electronic circuit using transistors or an IC. These circuits often do not take a wrong supply very well and it might be destroyed.
the source current is the current that flows from the power source.
I hope you mean the thermistor. If so,well it does not obey Ohms law. When current flows through the thermistor its temperature start increasing which reduces the resistance of the thermistor. A reduction in resistance at the same supply voltage will cause the current to increase. Thus it's not obeying Ohms law.
reciprocal of the square root of 2, converts from peak voltage to rms voltageAnother AnswerThis figure results when you work out how much work is done by one complete cycle of a.c. current. Since work is proportional to the square of a current, if you divide one complete cycle of a sine wave current into lots and lots of instantaneous values, square each of these values, find their average (mean) value, then find the square root of that value, you will have found the 'root-mean-square' of the current over a complete cycle. This value always works out to 0.707 x the peak or maximum value of the sine wave. For other waveforms, other r.m.s. values result.
The HOLD pin indicates that an external device wants the 8085 to stop and allow the external device to drive the bus. The acknowledge of control transfer is HLDA, however, it is important to note that HLDA does not mean the current cycle is complete - it means that the current cycle is the last cycle, at which point the 8085 will release the bus. (One half clock cycle later.)
Switch mode power supply (smps) converts 110-230 volts of alternating current to direct current that computer components need. The fan keeps the power supply cool.
EFFECTIVE HOW ABOUT AVERAGE .639 of peak.AnswerThe 'effective' value of an a.c. voltage (or current) is the same as its 'root-mean-square' (r.m.s.) voltage which, for a sinusoidal waveform, is 0.707 Umax.The 'average' value of an a.c. voltage (or current) is zero over a complete cycle, or 0.639 Umax, over half a cycle (usually applied to rectified waveforms).
The statement "the power supply must be toasted" is a rather idiomatic way of saying, the power supply must have been destroyed by excess current.
The time it takes to complete one cycle of a signal is called one period. For example, if the signal has a frequency of one hertz (one cycle per second), the period would be 1 second. A two hertz frequency would mean a ½ second period, or ½ second to complete one cycle.
Period length refers to the duration of time it takes for a complete cycle or revolution to occur. In different contexts, period length could refer to various cycles such as the menstrual cycle, a financial reporting period, or the time it takes for a wave to complete one full cycle.
Assuming that you mean connected to 120 Volts (V) supply, start with Power(P)=Current(I) x Voltage(V), and if P=V*I, then I=P/V. I=12W/120V=0.1A or 100mA and that is your current.
A bulb powered by AC supply generally provides more illumination than the same bulb powered by DC supply. This is because the higher voltage of AC supply allows more current to flow through the bulb, resulting in increased brightness.
I am a computer program, so I do not have a physical front yard. Would you like information on the water cycle instead?
Electrical current alone has no heating effect. Current through a device, with a voltage across the device will have a heating effect. The equation for calculating it is power = voltage x current, where power is proportional to the heating effect If the AC supply is measured as an RMS voltage and an RMS current and the device is resistive, then the heating effect will be identical to the same values with a DC supply. RMS means the "average" voltage or current of an AC supply whereas the peak AC voltage refers to the highest voltage that is reached on each cycle. However, if the device is not just resistive but is inductive, the heating effect will be lower with an AC supply than with a DC supply. By inductive, we mean that the device has a coil or capacitor, for example, in the circuit. The reasons why are outside the scope of this answer but are explained in many electronics text books, or look up "power factor" on google
earth remain Fly constrant over time though this does not mean that precipitation will increase