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1HP =746 watts power(watts)= current times voltage ... 746x500=373000. 373000/380= 981.58 so 981.58 amps
AnswerYou have not supplies sufficient information to answer the question.
The load current depends upon the type of motor(d.c./a.c./ single-phase/ three-phase), and the efficiencyof the motor. Before you can calculate the current, you need to determine the input power to the machine, which is always greater than its output power, which you have described as being 500 hp. Once you have determined the input power, and the type of motor, only then can you can calculate the load current
Wiki User
∙ 11y ago
Wiki User
∙ 13y agoYou did not specify everything needed to perform that calculation, so some things have been assumed, such as power factor (PF) = 0.92, efficiency (EFF) = 0.95, and voltage (three phase delta) = 4160.
- 125 HP times 746 watts per HP = 93 KW
- 93 KW divided by PF (0.92) divided by EFF (0.95) = 107 KVA
- 107 KVA divided by 3 = 36 KVA per winding
- 36 KVA divided by 4160 V = 8.5 amperes per winding
- 8.5 amperes times 1.732 (square root of 3) = 14.8 amperes per phase
This is a big motor, requiring special engineering, and most probably a star-delta MCC. You could theoretically run the motor on 480, but then the current would be 128 amperes per phase, drastically increasing the size of the conductors as well as the size of the motor.
Wiki User
∙ 11y ago746w=1hp so .5hp=373w and I=p/v so 373/380= 981.6mA
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Yes a 208 voltage motor will operate on 220 volts. You have to increase the motor overload protection by 10% of the motor's full load amperage to protect the motor.
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If the nameplate states 20 amps then that is the full load amperage when the motor is running. The start up current on the motor could reach 300% of the FLA depending on the type of motor and the load that is connected to the motor.
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FLA is the nameplate amperage rating of the motor when it is running at its designed horsepower and on the motors designed voltage. 746 watts = 1 HP. The FLA of a 1 HP motor at 240 volts would be W = amps x volts, Amps = Watts/Voltage. 746/240 = 3.1 amps full load. Overload the motor and the amps go higher, motor running at no load amps are lower than FLA
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what is the full load amps for 2.4 hp motor at 460 volts ?
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What wire size for world's simplest motor?
Wire size is based on the amperage of the load. Without knowing what the motors's full load amperage is, an answer can not be given.
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FLA is the nameplate amperage rating of the motor when it is running at its designed horsepower and on the motors designed voltage. 746 watts = 1 HP. The FLA of a 1 HP motor at 240 volts would be W = amps x volts, Amps = Watts/Voltage. 746/240 = 3.1 amps full load. Overload the motor and the amps go higher, motor running at no load amps are lower than FLA
What size armoured copper cable needed for 75 kW motor?
Wire sizing is based on the motors full load amperage. The amperage can be calculated but a voltage has to be stated. I = W/E. Amps = Watts/Volts. Restate the question with a voltage and an answer can be given.
What is FLA in electrical terms?
FLA = full load amps <<>> It is a term that is associated with motors. It is the amperage of the motor when it operates at its full rated horsepower under load.
How many Amps for 3 horsepower at 208 volts?
To calculate the amperage for 3 horsepower at 208 volts, use the formula: Amps = (HP x 746) / (Volts x Efficiency). Assuming 90% efficiency, the calculation would be: (3 x 746) / (208 x 0.90) = 10.69 Amps.
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The breaker should be sized to 250% of the motor's full load amperage.
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The first thing you have to do is find the full load amps of the motor. The wire size feeding the motor has to be 125% of the full load current. The breaker is usually 250% of the full load current. If the voltage and amperage had been added to the question the exact breaker size could have been calculated.
