what is common collector
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∙ 11y agoCommon emitter is the only transistor configuration that has an 180 degree phase difference between input and output. Common base and common collector outputs are in phase with the input.***********************************That is incorrect.The output of the common emitter is inverted, there is no phase shift.
+ve feedback
Simply connect the -ve of the bulb to -ve of the battery and +ve of bulb to +ve of battery using an electrically conductive wire, the bulb will light automatically.
Because as the signal voltage increases on the base, the base current increases this causes the collector current to increase, this decreases the voltage drop Vc to ground. As the base voltage decreases the base current decreases causing the Collector current to decrease, increasing the voltage drop Vc to ground. i think dis ans will clerify d doubts of students... ... in CE config.. as Vo=Vcc-Ic Rc nw as Vcc is const. v cn say Vo is directly proportional 2 (-Ic Rc) so nw when d base voltage is increased Ib will inc. thus, Ic will inc. cuz Ic=beta Ib thus Ic Rc drop increases... as Vo is prop 2 -Ic Rc thus, Vo will decrease...thus d curve for d +ve half cycle in which Ib is increasing drawn in 180 deg phase showing Vo is dec. n vice versa 4 -ve half cycle... nw in CC... as d o/p is taken frm emitter... Vo= Ie Re so der's no -ve sign..n for d +ve cycle Ie will incr(dat's leakage current) as der's no-ve sign it'll b in phase wid i/p..hence no phase shift as leakage current doesnt incr. so much thus,d o/p voltage Ie Re doesnt inc much thus, d o/p doesnt amplify much thus dis config knwn as emiter follower... nw in CB,... d I/P is appiled at emitter n o/p is taken frm collector... so, 4 d +ve half cycle d Eb junc will b more FB thus causing incr. in Ib n thus, in Ic... so inc. in Ic causes inc. in o/p voltage..n during -ve half cycle d junc will b less FB so o/p voltage will b decreasing..hence der's no phase shift... for any other help.. cont.- shrey.dhingra51@gmail.com
in the series circuit elements are one behind the other ie +ve terminal of one element is connected to the -ve of other element of the circuit whenever in parallel circuits the elements are parallely connect ie all +ve terminal are connected at a point and all -ve terminals of the elements are connected at a point.
Common emitter is the only transistor configuration that has an 180 degree phase difference between input and output. Common base and common collector outputs are in phase with the input.***********************************That is incorrect.The output of the common emitter is inverted, there is no phase shift.
+ve feedback
collector base is reverse biased (connect n region to be +ve terminal &p region to - ve terminal .due to forward biasing at emittor base juntion electrons follow from emittor to base .
pacha ve
ve can find out quadratic equations
Caesium hydride. CsH . ionically it is 'Cs^+' & 'H^-'
Division by negative numbers follow the same rule as multiplication. That is, (-ve and +ve) or (+ve and -ve) make -ve (-ve and -ve) or (+ve and +ve) make +ve. So the absolute value of 3/(-3) is 1 and the sign is (+ve and -ve) = -ve so that the answer is -1.
Base voltage in a transistor. There is also Vc (Collector voltage), Ve(Emitter voltage), Ic(Collector current), Ib(Base current), Ie(Emitter current), Vcc(Supply voltage), and Hfe (Forward current gain)
Imran Khan are 2 in Bollywood. One is a Punjabi singer and other Actor. The best song of singer is Amplifier.
Have a common ground and separate the +ve to each of the LEDS
Asking about biasing of the emitter alone does not make sense. When you talk about bias, you talk about a junction, such as emitter-base or emitter-collector or base-collector. In a bipolar junction transistor (BJT) both the emitter-base and emitter-collector need to be forward biased, otherwise you are operating the BJT in cutoff mode. Certainly, if you intend to operate the BJT as a switch, then reverse bias for emitter-base (actually, zero bias) could well be one of the valid states, corresponding to a cutoff condition for emitter-collector. However, operation in linear mode, the other normal way to use a BJT, requires that both the emitter-base and the emitter-collector be forward biased. Of course, depending on the ratio of emitter-base to emitter-collector versus hFe, you could also be saturated, which is a non-linear mode, i.e. an on switch.
A+ve A1+ve O+ve