There is no such thing. When declaring a friend function only the explicitly-scoped friend is granted private access. The friend function may well be declared virtual within its own class but none of its overrides are granted access unless they are explicitly granted access.
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A constructor is a method that fires when the object is instantiated. A friend function is a function that has special access to the object. They are two different types of things, and cannot be further differenced.
One of the main goals kept in mind while Java was being developed was that they wanted it to be like C++, but without all the features which make the language overly complex and messy. These features include things like (true) multiple inheritance, operator overloading, and friend functions.
A normal function is any function that is not a member of any class. Normal functions that operate upon a class are referred to as non-member functions, however a non-member function can also be a member of another class. Any class may declare any non-member function to be a friend of the class, in which case the function becomes a friend function.A member function is a member of a class and may be declared static or non-static. Non-static member functions have the following 3 properties:Private access to the class members.Scoped to the class.Must be invoked against an object of the class (has a 'this' pointer).Static member functions have the first two properties only while friend functions have the first property only. Non-member functions that are not friends of the class have none of these properties.
The only function of a friend is to extend the private class interface outwith the class, essentially making the friend part of the class interface.
Assignment(=) operator is a special operator that will be provided by the constructor to the class when programmer has not provided(overloaded) as member of the class.(like copy constructor). When programmer is overloading = operator using friend function, two = operations will exists: 1) compiler is providing = operator 2) programmer is providing(overloading) = operator by friend function. Then simply ambiguity will be created and compiler will gives error. Its compilation error.