this shows you everything you need about them Pin Number Description 1 A Input Gate 1 2 B Input Gate 1 3 Y Output Gate 1 4 A Input Gate 2 5 B Input Gate 2 6 Y Output Gate 2 7 Ground 8 Y Output Gate 3 9 B Input Gate 3 10 A Input Gate 3 11 Y Output Gate 4 12 B Input Gate 4 13 A Input Gate 4 14 Positive Supply
If you look at the 7486 IC datasheet you can see, it have 4 independence XOR gates with 2 inputs. So you can only use 2 inputs if you see it like that. But if you understand the truth table of XOR gate you can have 3 input application using 7486 IC. Here I will show you how. 1.Get the first 2 input into the first XOR gate. 2.Then get the 3rd input together with the Output from the first 2 input XOR gate into another gate. 3.This output should be the result of 3 input XOR gate. Check this output with 3 input truth table to confirm the answer.
To produce a 3-input OR gate when only 2-input OR gates are available: Use 3 OR gates Inputs to Gate A are input 1 and input 2 Input to Gate B is input 3 (if 2 inputs are necessary, include input 3 and FALSE) Inputs to Gate C are outputs from Gate 1 and Gate 2 === If input 1 OR 2 is TRUE, output of Gate A will be TRUE. If input 3 is TRUE, output of Gate B will be TRUE. If output of Gate A OR Gate B is TRUE, output from Gate C will be TRUE. That is if one ore more of Inputs 1, 2 or 3 is TRUE, the result will be TRUE. Otherwise, output of Gate C will be FALSE.
L293D is having 20 pin IC and also 16 pin IC. description of 20 pin is: 1-enable 1 2- input 1 3- output 1 4,5,6,7,14,15,16,17- ground 8- output 2 9- input 2 10,20-vs 11-enable 2 12- input 3 13-output 3 18-output 4 19-input 4 description for 18 pin: 1-enable 1 2- input 1 3- output 1 4,5,12,13- ground 6-output 2 7- input 2 8,18-vs 9-enable 2 10-input 3 11-output 3 14-output 4 15-input 4
NOR gate = not(A or B) = A nor BAND gate = A and BAND gate = not(not A or not B)AND gate = not(not(A or A) or not(B or B))AND gate = (A nor A) nor (B nor B)Therefore using 2 input NORs to make a 2 input AND you need three NORs. If you wanted something different (e.g. a 5 input AND) the above proof can be modified appropriately to get your answer.
this shows you everything you need about them Pin Number Description 1 A Input Gate 1 2 B Input Gate 1 3 Y Output Gate 1 4 A Input Gate 2 5 B Input Gate 2 6 Y Output Gate 2 7 Ground 8 Y Output Gate 3 9 B Input Gate 3 10 A Input Gate 3 11 Y Output Gate 4 12 B Input Gate 4 13 A Input Gate 4 14 Positive Supply
IC 7402 is different from the other type of IC like 7404,7408,7432 and 7400 when it is connected to have an output desired... if you noticed all i mentioned ic is connected from left to the right. input pin 1 and 2, output pin 3 input pin 4 and 5, output pin 6 input pin 13 and 12, output pin 11 input pin 10 and 9, output pin 8 while in nor gate, to have the desired output it must be connected from right to left... input pin 2 and 3, output pin 1 input pin 5 and 6, output pin 4 input pin 8 and 9, output pin 10 input pin 11 and 12, output pin 13
To produce a 3-input OR gate when only 2-input OR gates are available: Use 3 OR gates Inputs to Gate A are input 1 and input 2 Input to Gate B is input 3 (if 2 inputs are necessary, include input...
output is feedback in input
A 2 input NAND gate requires 4 NOR gates.A 3 input NAND gate requires 5 NOR gates.A 4 input NAND gate requires 6 NOR gates.etc.
For two input AND gate it is 7408for three input AND gate it is 7411
If you look at the 7486 IC datasheet you can see, it have 4 independence XOR gates with 2 inputs. So you can only use 2 inputs if you see it like that. But if you understand the truth table of XOR gate you can have 3 input application using 7486 IC. Here I will show you how. 1.Get the first 2 input into the first XOR gate. 2.Then get the 3rd input together with the Output from the first 2 input XOR gate into another gate. 3.This output should be the result of 3 input XOR gate. Check this output with 3 input truth table to confirm the answer.
You would connect the output of the first AND gate to one input of the second AND gate. You are left with 2 inputs on the first AND gate and 1 input on the second AND gate. The final output is from the second AND gate.
The 7432 is a TTL (transistor-transistor logic) digital silicon integrated circuit with four 2-Input OR gates usually in a 14 pin DIP (dual inline package). It operates on a single 5VDC supply. A low input (false) must be an active pulldown below 0.8V, a high input (true) must be above 2.0V while the inputs naturally float above this voltage if not driven unused inputs should be passively pulled up with resistors to reduce noise pickup. A low output (false) will not be above 0.4V, a high output (true) will not be below 2.4V.The 7432 itself was released in the late 1960s and is currently obsolete and nearly impossible to find, new designs should use the newer equivalent parts 74LS32 (low power schottky TTL), 74HC32 (high speed CMOS), etc. which can also operate at much higher speeds (and some at lower voltages for lower power consumption).The pinout of the 7432 and its equivalents in the usual 14 pin DIP is:A Input Gate 1B Input Gate 1Y Output Gate 1A Input Gate 2B Input Gate 2Y Output Gate 2GroundY Output Gate 3A Input Gate 3B Input Gate 3Y Output Gate 4A Input Gate 4B Input Gate 4Positive Supply
The 7812 is not a logic gate. It is a three terminal voltage regulator with an output of +12V.Looking at the pins of the TO-220 device, with the flat side down, the left pin and the case is common, the center pin is input,and the right pin is output. For the smaller TO-92 78L12 device, the left pin is output, the center pin is common, and the right pin is input
an 2 input AND gate can be realize using 3 NOR gates.Let ,A and B are the input and x be the output.x=A.B= NOR(NOR(A) NOR(B))
To produce a 3-input OR gate when only 2-input OR gates are available: Use 3 OR gates Inputs to Gate A are input 1 and input 2 Input to Gate B is input 3 (if 2 inputs are necessary, include input 3 and FALSE) Inputs to Gate C are outputs from Gate 1 and Gate 2 === If input 1 OR 2 is TRUE, output of Gate A will be TRUE. If input 3 is TRUE, output of Gate B will be TRUE. If output of Gate A OR Gate B is TRUE, output from Gate C will be TRUE. That is if one ore more of Inputs 1, 2 or 3 is TRUE, the result will be TRUE. Otherwise, output of Gate C will be FALSE.