1111111111111111 (216 - 1 = 65535)
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A 16-bit number is a number made of 16 binary digits. The largest 16-bit number is 1111111111111111 in binary (sixteen 1s), which is equal to 65535 in decimal.
This is presuming that you are using an 'unsigned' 16-bit number, which can store numbers from 0 to +65535. If you want to be able to store negative numbers as well, 16-bits will let you store numbers from -32768 to +32767, if you use the two's-complement method for storing a 'signed' value.
Just as with the base 10 numbering system, there is no 'largest number' in binary. Whichever number you think of as the largest can always be made larger by the addition of an extra digit on the end. Infinity exists in all bases, but by its nature does not take an integer value.
But if you are talking about a specific amount of bits (in a computer) to represent a number, then there is. Example: 1 byte (8 bits) can hold values from 0 to 255 (decimal). 2 bytes (16 bits) can represent 0 to 65535. Sometimes, one of the bits will be designated as a sign bit (say 0 for positive and 1 for negative, I can't remember which one is normally used). In that case, 16 bits could represent from -32768 to +32767. In 64 bits could represent numbers from 0 to the order of 1.84 x 1019. And there is 128 bits (used in some encryption algorithms) could represent about 3.4 x 1038 different numbers. Usually we don't deal with just integers, in calculations though. So one way is to represent the 'floating point' portion with a certain number of bytes, then have another set of bytes to represent the 'exponent' (Like in scientific notation)
It's 16,383 for integer values or 16,384 for counting values.
14 bits, unsigned, allows you to express 16,384 values; if you want to include zero, which generally you do, the limit is one less.
Of course, if you're not trying to express every integral value, you can use 14 bits to express a number as big as you want; say, have the machine interpret the value as an exponent for some other number. If your base is 10, then the largest value would be 1 with 16,383 zeros after it. Of course, it'd be impossible to express a value like 7 that way!
The largest number in 16-bit binary is 65535 and is represented by 11111111-11111111.
In unsigned notation, 0xFFFF (65,535 decimal) is the largest value that will fit in a 16-bit register. In signed notation, 0x7FFF (32,767 decimal) is the largest because the most-significant bit denotes the sign.
In C: result = value & ~0xFFDF
127.
Quite simply, a 16-bit compiler is a compiler for a 16-bit machine.
16 bit compilers compile the program into 16-bit machine code that will run on a computer with a 16-bit processor. 16-bit machine code will run on a 32-bit processor, but 32-bit machine code will not run on a 16-bit processor. 32-bit machine code is usually faster than 16-bit machine code.-DJ CraigNoteWith 16 bit compiler the type-sizes (in bits) are the following: short, int: 16long: 32long long: (no such type)pointer: 16/32 (but even 32 means only 1MB address-space on 8086)With 32 bit compiler the object-sizes (in bits) are the following:short: 16int, long: 32long long: 64pointer: 32With 64 bit compiler the object-sizes (in bits) are the following:short: 16int: 32long: 32 or 64 (!)long long: 64pointer: 64[While the above values are generally correct, they may vary for specific Operating Systems. Please check your compiler's documentation for the default sizes of standard types]Note: C language itself doesn't say anything about "16 bit compilers" and "32 bit compilers"