beta dc= ic/ib!!
Ie=Ic+Ib
Ib =Ic /beta beta is the gain factor of the amp.
IB=IE-IC =100uA
Actually the current gain is equal to Beta+1, not Beta. The current from/into the emitter is the sum of the current into/from the collector and base. Of course this assumes linear operation.For a proof: Ie + Ib + Ic = 0Ic = Beta * IbIe + Ib + Beta * Ib = 0Ie + (Beta + 1) * Ib = 0Ie = -(Beta + 1) * Ib
start at Ic'= Ic1+Ic2 Ib'=Ib1 Ic1=B1*Ib' Ie1=Ib2=Ib'(B1+1)=Ib'B1 + Ib' Ic' = Ib'*B1 + Ic2 Ic2= B2(Ib'B1+Ib') Ic' = Ib'B1 + Ib'B1B2 + Ib'B2 divide by Ib' Ic'/Ib'= current gain =B'=B1+B2+B1B2 note: calculations without resistance
Emitter current can be summed up by the formula: IE = IC+ IB Where IE = Emitter Current, IC = Collector Current, and IB = Base Current So simply take IE - IC and you'll get an IB of about 100uA. (5mA-4mA = .1mA or 100uA) Also, remember that IB controls IC and IE, not the other way around. You can also determine IB if Beta is known by the formula: IC = IB * Beta Which can be manipulated to equal IB = IC/Beta Hope this was helpful.
Sometime between the mid 1950s and 1968.
beta dc= ic/ib!!
Ie=Ic+Ib
Because the operation of the transistor is determined by the current at the base. the principle equations of BJT operation are: Ic = h*Ib ,and Ie=Ib+Ic thus device operation is controlled by the input current.
An integrated circuit contains multiple diodes and transistors on silicon. A processor performs the calculations in a computer.
Consider that current flow "enters" at the emitter and "exits" at the collector and base. Now, IE = IB + IC. Alternately, current "enters" at the collector and the base, and "exits" at the emitter. Now, IE = IB + IC
alpha is the common base current gain = Ic/Ie.beta is the common emitter current gain = Ic/Ib.
Ib =Ic /beta beta is the gain factor of the amp.
-ic is the suffix. This suffix means in relation of.
IB=IE-IC =100uA