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I think you mean operation overlord??? It is the American, Canadian and British offensive on Europe in World War 2. They landed in Normandy on 6th June 1944 (Commonly called D-Day, Day of Days or Deliverance Day) and progressed throughout France liberating Paris on the 25th August. This allowed the allies a foothold in Europe.
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SteveOperator overloading allows us to provide new implementations for existing operators. Not all languages support operator overloading; C does not, but C++ does. All languages provide built-in operators, however these operators cannot cater for user-defined types (they only work on built-in types). Operator overloading allows us to add this (missing) functionality so we can operate upon user-defined types as intuitively as we can with built-in types. In languages that do not support operator overloading, user-defined functions can be used instead of operators, but they are much less intuitive.
There is no concept of operator overloading in java, at least it is not available to the developers. There are still instances of operator overloading as in the case of "+" operator. It is used both to perform arithmetic sum as well as concatenation of two strings.
But one cannot impart additional functions to an existing operator as in the case of C++.
I think you mean operation overlord??? It is the American, Canadian and British offensive on Europe in World War 2. They landed in Normandy on 6th June 1944 (Commonly called D-Day, Day of Days or Deliverance Day) and progressed throughout France liberating Paris on the 25th August. This allowed the allies a foothold in Europe.
Java does not support operator overloading. Operator overloading is the scenario where you overload a particular operator to do something that it is not designed to do.
Ex: if you make the operator "*" do addition or the operator "-" do multiplication, imagine the chaos that would ensue in your program. So the java designers blocked this feature of operator overloading.
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Operator overloading is possible in java or not?
Java does not support opperator overloading, so the answer to your question is: none.
How operator overloading differ from function overloading?
Function overloading is multiple definition with different signatures(the parameters should be different) for the same function. The parameter list have to be different in each definition. The compiler will not accept if the return type alone is changed. Operator overloading is defining a function for a particular operator. The operator loading function can not be overloaded through function overloading.
How can you differentiate overloading of pre-fix and post-fix increment operator?
The prefix increment operator is overloaded as operator++() while the postfix increment operator is overloaded as operator++(int).
What are the disadvantage of operator overloading?
The only disadvantage of operator overloading is when it is used non-intuitively. All operators must behave with predictable results, thus it makes no sense to implement the plus (+) operator so that it behaves like a subtract (-) operator, or a multiply (*) operator, or indeed anything other than the intuitive sum of two objects.
How do you find largest of two object using operator overloading in c?
I will not use operator overloading in C# to do anything. Operator overloading may lead to one operator has more than 1 semantic meaning. For example, we know 1 + 2 yields 3, and "1" + 2 yields "12". I do not like this overloading of the operator + being used for addition in Number hierarchy, while as the concatenation in strings. That is, one operator (+) has 2 significant semantics.And the question "find largest of two object" is too vague - what do you mean "largest"? and object? We know apple and orange are 2 objects, but how do you compare them, and find the largest one?????? (size, price or what???)
