A spanning tree is a tree associated with a network. All the nodes of the graph appear on the tree once. A minimum spanning tree is a spanning tree organized so that the total edge weight between nodes is minimized.
yes, but a shortest path tree, not a minimum spanning tree
Minimum cost spanning tree is used for Network designing.(like telephone, electrical, hydraulic, TV cable, computer, road)
Kruskal's algorithm is an algorithm in graph theory that finds a minimum spanning tree for a connected weighted graph. This means it finds a subset of the edges that forms a tree that includes every vertex, where the total weight of all the edges in the tree is minimized. If the graph is not connected, then it finds a minimum spanning forest (a minimum spanning tree for each connected component). Kruskal's algorithm is an example of a greedy algorithm.
o(eloge)
A spanning tree is a tree associated with a network. All the nodes of the graph appear on the tree once. A minimum spanning tree is a spanning tree organized so that the total edge weight between nodes is minimized.
yes, but a shortest path tree, not a minimum spanning tree
STP (Spanning Tree Protocol) is still referred to as STP. However, there are newer variations of STP such as Rapid Spanning Tree Protocol (RSTP) and Multiple Spanning Tree Protocol (MSTP).
While the other, more technical answer is correct, a simpler answer would be to just say that with a sink tree, each item or category leads to the next and no attempt is made to connect them to each other. A spanning tree would make those connections between categories and items, and would be far more complex on each level. Envision a large house with many doors. There may be many ways to get to the living room from each part of the house, but the sink tree would list the shortest, and then the shortest to the living room, etc., whereas a spanning tree would list all probable pathways from one category to another,
The port will rapidly transition to forwarding.
A spanning tree protocol, or STP, is characteristic to a LAN. It provides a loop-free topology for networks within the system.
no difference,,,tree and hybrid are same.
Minimum spanning trees can be found using algorithms like Prim's algorithm or Kruskal's algorithm. These algorithms work by starting with an empty spanning tree and iteratively adding edges with the smallest weights until all vertices are connected. The resulting tree will have the minimum total weight possible.
Minimum cost spanning tree is used for Network designing.(like telephone, electrical, hydraulic, TV cable, computer, road)
Proving this is simple. First, you prove that G has a spanning tree, it is connected, which is pretty obvious - a spanning tree itself is already a connected graph on the vertex set V(G), thus G which contains it as a spanning sub graph is obviously also connected. Second, you prove that if G is connected, it has a spanning tree. If G is a tree itself, then it must "contain" a spanning tree. If G is connected and not a tree, then it must have at least one cycle. I don't know if you know this or not, but there is a theorem stating that an edge is a cut-edge if and only if it is on no cycle (a cut-edge is an edge such that if you take it out, the graph becomes disconnected). Thus, you can just keep taking out edges from cycles in G until all that is left are cut-gees. Since you did not take out any cut-edges, the graph is still connected; since all that is left are cut-edges, there are no cycles. A connected graph with no cycles is a tree. Thus, G contains a spanning tree. Therefore, a graph G is connected if and only if it has a spanning tree!
Proving this is simple. First, you prove that G has a spanning tree, it is connected, which is pretty obvious - a spanning tree itself is already a connected graph on the vertex set V(G), thus G which contains it as a spanning sub graph is obviously also connected. Second, you prove that if G is connected, it has a spanning tree. If G is a tree itself, then it must "contain" a spanning tree. If G is connected and not a tree, then it must have at least one cycle. I don't know if you know this or not, but there is a theorem stating that an edge is a cut-edge if and only if it is on no cycle (a cut-edge is an edge such that if you take it out, the graph becomes disconnected). Thus, you can just keep taking out edges from cycles in G until all that is left are cut-gees. Since you did not take out any cut-edges, the graph is still connected; since all that is left are cut-edges, there are no cycles. A connected graph with no cycles is a tree. Thus, G contains a spanning tree. Therefore, a graph G is connected if and only if it has a spanning tree!
A tree is one tree and a forest is many trees.