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V=voltage at 4amperes, 12.2V I=Ampere, 4A V V= E-Ir r=(E-V)/I r=(12.6-12.2)/4 r=0.1 ohm

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Q: What if your car battery measures 12.6V with no current being drawn from it when you turn your headlights on which draws 4A each the voltage drops to 12.2V what is the internal resistance of the batte?
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011.1