If a short occurs in a resistor in series with other resistors, the voltage drops across the other resistors will increase.
If a short occurs in a resistor in parallel with other resistors, the voltage drops across the other resistors will decrease, to zero.
You could use the voltage divider rule to reduce the voltage. Using two resistors in series, the input voltage will drop across each resistor by an amount that is proportionate to the values of the resistors. If the 1st resistor is 10K and the 2nd resistor is 100K, the voltage drop across the 10K will be 10 times LESS than that of the 100K resistor. The total voltage drop across both resistors will be equal to the supplied input voltage. Work out the ratio of voltage you need from the total input voltage and use 2 resistors will that give you the same ratio. Connect the LEDs in parallel with the resistor the gives you the voltage you want. Use a MM to measure the voltage across the resistor before wiring LEDs.
I observe that the total effective resistance of several resistors in series is the sum of the individual resistance values of the individual resistors.
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By Ohm's law, current is voltage divided by resistance.In order to determine which circuit draws more current, you need to look at voltage and resistance. Assuming similar voltage, then, less resistance would result in more current.Now you need to know the values of the resistors in both cases. You did not state those important pieces of information. The net resistance of two resistors, R1 and R2, in parallel is R1 time R2 divided by (R1 plus R2). All you need to do is calculate for the two cases.If the two resistors were the same, you can generalize the answer by saying that, with contant voltage, two similar resistors in parallel will pull more current than one similar resistor - specifically, two will pull twice the current of one.
current in series depends on values of resistors. more resistance less current will flow through and viceversa
The total voltage across resistors in a series circuit is the sum of the individual voltages across each resistor. The resistor values do not affect the total voltage as long as they are connected in series.
lf all resistors are in parallel, yes. If they are in series, not necessarily - this depends on the resistor values (if they are all the same, then yes, if not no).
You could use the voltage divider rule to reduce the voltage. Using two resistors in series, the input voltage will drop across each resistor by an amount that is proportionate to the values of the resistors. If the 1st resistor is 10K and the 2nd resistor is 100K, the voltage drop across the 10K will be 10 times LESS than that of the 100K resistor. The total voltage drop across both resistors will be equal to the supplied input voltage. Work out the ratio of voltage you need from the total input voltage and use 2 resistors will that give you the same ratio. Connect the LEDs in parallel with the resistor the gives you the voltage you want. Use a MM to measure the voltage across the resistor before wiring LEDs.
If three equal resistors are connected in parallel, the equivalent resistance will be one-third of the resistance in series. This lower resistance will result in a higher current flowing through the resistors when connected in parallel compared to when they are in series. Therefore, the power dissipated by the resistors in parallel will be greater than 10W.
I observe that the total effective resistance of several resistors in series is the sum of the individual resistance values of the individual resistors.
A: No matter how many resistor of different value are inserted the current will remain the same for each. The voltage drop will vary with the difference in resistors and i a parallel path is found along the way the current will divide according to the resistors values
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Experimental calculations should use measured values of resistors, because actual resistors can deviate slightly from their color-coded values due to manufacturing tolerances. Using measured values ensures more accurate results in experiments where resistor values play a critical role.
In parallel circuit the current through the resistors are different in values depending upon the values of resistors. But the sum of the currents across all the resistors will be equal to the current through the sourcgsvg bdjasuhafyuhda
The total resistance of resistors in series is simply the sum of the resistance values of those resistors. If the resistors are identical, then you can multiply the resistance of one of them by the number of resistors in the circuit.
carbon resistors of standard values are manufactured because other values can be obtained by series and parallel combination of standard values. Moreover even standard values do not offer exact Resistance's will have tolerance
By Ohm's law, current is voltage divided by resistance.In order to determine which circuit draws more current, you need to look at voltage and resistance. Assuming similar voltage, then, less resistance would result in more current.Now you need to know the values of the resistors in both cases. You did not state those important pieces of information. The net resistance of two resistors, R1 and R2, in parallel is R1 time R2 divided by (R1 plus R2). All you need to do is calculate for the two cases.If the two resistors were the same, you can generalize the answer by saying that, with contant voltage, two similar resistors in parallel will pull more current than one similar resistor - specifically, two will pull twice the current of one.