same as decade resitance box but instead of reitances there wil be capacitances
The voltage distribution across insulator strings is not equal, this because exist capacitances beteween insulators and tower and between insulators and conductor. So how i can calculate the stray capacitances across insulator strings?
For capacitors connected in parallel the total capacitance is the sum of all the individual capacitances. The total capacitance of the circuit may by calculated using the formula: where all capacitances are in the same units.
When capacitors are connected in parallel, the total capacitance in the circuit in which they are connected is the sum of both capacitances. Capacitors in parallel add like resistors in series, while capacitors in series add like resistors in parallel.
Parasitic capacitances form across every depletion region there's also a capacitance between the conductive leads to the terminals. For simplicity they are usually just lumped to each of the terminals of the transistor. Gate, Drain, Source and Substrate. If substrate is shorted to source creating typical 3 terminal representation then that half of those parasitic capacitances combine and Css (source-substrate) = 0. Cgd Cgs Cds (primarily from drain to substrate, not drain to source)
same as decade resitance box but instead of reitances there wil be capacitances
The voltage distribution across insulator strings is not equal, this because exist capacitances beteween insulators and tower and between insulators and conductor. So how i can calculate the stray capacitances across insulator strings?
For capacitors connected in parallel the total capacitance is the sum of all the individual capacitances. The total capacitance of the circuit may by calculated using the formula: where all capacitances are in the same units.
When capacitors are connected in series, their total capacitance decreases. This is because the total capacitance is inversely proportional to the sum of the reciprocals of the individual capacitances. The voltage across each capacitor remains the same.
The equivalence capacitance of capacitors in series is calculated using the formula: ( \frac{1}{{C_{eq}}} = \frac{1}{{C_1}} + \frac{1}{{C_2}} + \dots ), where ( C_{eq} ) is the total capacitance. For capacitors in parallel, the total capacitance is the sum of the individual capacitances: ( C_{eq} = C_1 + C_2 + \dots ).
Since the total capacitance for capacitors in parallel is the sum of the individual capacitances. I'm sure that you can work it out for yourself!
inductance
The best way is to use an EM solver, such as FastCap from MIT. Numerous published papers also describe the best-fit formulae to calculate fringing capacitances by hand. Try reading "Modeling of interconnect capacitance, delay , and crosstalk in VLSI," by Wong et al., IEEE Trans. Semi. Manufacturing, v13, n1, February 2000, pp108, and the references therein.
When capacitors are connected in parallel, the total capacitance in the circuit in which they are connected is the sum of both capacitances. Capacitors in parallel add like resistors in series, while capacitors in series add like resistors in parallel.
increase the capacitance of the capacitor by a factor of two. This is because capacitance is directly proportional to the area of the plates.
Parasitic capacitances form across every depletion region there's also a capacitance between the conductive leads to the terminals. For simplicity they are usually just lumped to each of the terminals of the transistor. Gate, Drain, Source and Substrate. If substrate is shorted to source creating typical 3 terminal representation then that half of those parasitic capacitances combine and Css (source-substrate) = 0. Cgd Cgs Cds (primarily from drain to substrate, not drain to source)
The relationship between amperage and capacitance is indirect. Capacitance stores and releases electrical energy, affecting the flow of current in a circuit. Higher capacitance can lead to slower changes in current (i.e., lower frequency), while lower capacitance can result in faster changes in current.