Answer It is both 8 bit processors in a 40 pin package but it is not pin compatible, it have almost the same functions but it is very difficult to compare the two because it is not the same family.
The microcontrollers have an 8-bit data bus. They are capable of addressing 64K of program memory and a separate 64K of data memory. The 8051 has 4K of code memory implemented as on-chip Read Only Memory (ROM). The 8051 has 128 bytes of internal Random Access Memory (RAM). The 8051 has two timer/counters, a serial port, 4 general purpose parallel input/output ports, and interrupt control logic with five sources of interrupts. Besides internal RAM, the 8051 has various Special Function Registers (SFR), which are the control and data registers for on-chip facilities. The SFRs also include the accumulator, the B register, and the Program Status Word (PSW), which contains the CPU flags. << SHARMILA TANDEL (B.E) ELECTRONICS >>
the 8051 microcontrroller is the name doesnt matter easy or not....but the maiin and imp diff between both is at89s51 represents the 8051 chip no....along with the name of company i.e atmel, so all n all both are same thing ...... 89c51 have RISC architecture and contains less no of opcodes which are easy for programming. so iti is preferred than 8051.
Text files do not contain int types, only char types. Alternating between the two when reading a text file is an exercise in futility. The assumption here is that the text file contains integers in string form. To extract the integers you must convert the digits into values. The digit '4' is not a number; four is the number, 4 is just the symbol for the number four. However, '4' is ASCII character code 52, thus if we subtract 48 we get its value. Character '0' is ASCII 48, thus subtracting '0' is the same as subtracting 48. If 0 <= value <= 9, then we know the character is a digit. The following example demonstrates how to extract integers from strings. The code can be easily adapted to extract integers from text files. #include <iostream> int main() { char str[] = "This is a string that has 54 characters and 2 numbers."; std::cout << "'" << str << "'\n" << std::endl; int idx = 0; again: int number = 0; while( str[idx] ) { char value = str[idx++] - '0'; if( value >= 0 && value <= 9 ) { number *= 10; number += value; } else if( number ) break; } if( number ) std::cout << "The number " << number << " was found in the string." << std::endl; if( str[idx] ) goto again; return( 0 ); } Output: 'This is a string that has 54 characters and 2 numbers.' The number 54 was found in the string. The number 2 was found in the string.
Memory page.
Pages
4k it is...$4.000.00...
-4k-2=10 -4k=10+2 -4k=12 k=-3
4k-100 = -96
8-4k = 40 (4k-8) - 8 = 40-8 4k = 32 4k/4 = 32/4 k =8
Yes, 4K is $4000.
around $4k around $4k
4k-64 = -60
4k-7 = 7 4k = 14 k = 3.5 or k = 7/2
Well if you're going for a huge dph Pokemon then you should probably teach him the dirty sanchez, because it does 4k damage on crit.
31 = 3-4k 31-3 = -4k 28 = -4k Divide both sides of the equation by -4 to find the value of k: k = -7