Statement S2 is anti-dependent on statement S1 if S2 follows S1 in program order and if the output of S2 overlaps the input of S1. The anti-dependence S1 to S2 define as cross arrow such as S1 |-> S2.
strlen(s1) to find the length of the string s1 strcpy(s1,s2) copy source string to destination string(i.e copies s2 to s1,s2 remain unchanged) strcmp(s1,s2) compares s1 and s2 and prints 0 if s1 and s2 are equal,-1 if s2 is greater, 1 if s1 is greater strcat(s1,s2) combines string s1 and s2 to a single word and stores it in s1 strupr() converts lower case string to upper case strlwr() converts upper case string to lower case
char *strmerge (char *s3, const char *s1, const char *s2) { strcpy (s3, s1); strcat (s3, s2); return s3; }
unsigned char * memcpy(unsigned char * s1, unsigned char * s2, long size) { long ix; s1= (char *)malloc(sizeof(strlen(s2))); for(ix=0; ix < size; ix++) s1[ix] = s2[ix]; return s1; }
/* ellipses, ..., used to emulate indentation */ int strcmp (const char* s1, const char* s2) { ... while (s1 != NULL && s2 != NULL) { /* scan both strings */ ... ... if (*s1 < *s2) return -1; /* first string less */ ... ... if (*s1 > *s2) return 1; /* first string greater */ ... ... s1++; ... ... s2++; ... } ... if (s1 == s2) return 0; /* strings equal or both empty */ ... if (s1 != NULL) return 1 else return -1; /* first string longer(1) / shorter(-1) */ } A slightly less computation-intensive version is: int strcmp(const char* s1, const char* s2) { ... if (s1==s2) ... ... return 0; ... while (*s1) ... ... if (*s1++^*s2++) ... ... ... if (--s1<--s2) ... ... ... ... return -1; ... ... ... else ... ... ... ... return 1; ... return 0; }
It cannot be proven because it is not true. Suppose S1 = {0,1,2,3} and S2 = {0,5,10} then S1 u S2 = {0,1,2,3,5,10} then |S1| = n = 4, |S2| = m = 3 but |S1 u S2| = 6 which is NOT n+m = 7
s=6
s2 + 4s - 32 = 0 What two factor of - 32 add up to 4? (s - 4)(s + 8) s = 4 ===
This quadratic equation has no solutions because the discriminant is less than zero.
A regular hexagon can be divided into 6 equilateral triangles. If a side equals S, then altitude equals S*sqrt(3)/2, and area of that triangle is (S2)*sqrt(3)/4. So the whole hexagon area is 6*(S2)*sqrt(3)/4 = 3*(S2)*sqrt(3)/2. Since S = perimeter/6, then you have: Area = Perimeter2*sqrt(3)/24.
it's called the formula for an area A=LW (area for a rectangle) (area equals length times width) A=S2 (area for a square) (area equals side squared)
s2= love
Force, in Newtons, can be expressed as Kg*m/s2. Acceleration can be expressed as m/s2. If you divide it out, you get:= N / (m/s2)
"g" simply means the gravitational constant at standard condition or at sea level. 9.8 m/s2 is the "g" in it's metric form. While 32.2 ft/s2 is in it's English form. When any of the two would be converted to the other the values would be approximately the same.
A quadratic equation (t=s2+3). This kind of line will result in a parabola like curve.
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