answersLogoWhite

0

question is not clear. RMS is .707 of peak. If you're asking about sums of currents or voltages represented by sine waves and they don't have the same frequency then the sum's RMS value is the square root of the sum of the squared amplitudes of the two waves. The squared amplitudes are proportional to the power in each current or voltage and the result represents the sum of the powers.

If the two sine waves have the same frequency then the sum's RMS value is the sum of the two RMS values. The physical circuit has to add power to the signal. (if the amplitudes are equal the resultant will have 4 times the power)

User Avatar

Wiki User

16y ago

Still curious? Ask our experts.

Chat with our AI personalities

SteveSteve
Knowledge is a journey, you know? We'll get there.
Chat with Steve
DevinDevin
I've poured enough drinks to know that people don't always want advice—they just want to talk.
Chat with Devin
CoachCoach
Success isn't just about winning—it's about vision, patience, and playing the long game.
Chat with Coach
More answers

The RMS value of a sine wave is the "Effective" or "Working" value of a sine wave. That is, the amount of power produced by a amount of current (Amperes). So for example, in your house, the power you would read is say, 120 Volts RMS. In actuality, you are getting 170 volts (if you round it). This 170 volts is the voltage you would get at the "Peak" (90 degrees into the sine wave). A way to find the RMS is done by this.

RMS= Peak Voltage X .707

User Avatar

Wiki User

15y ago
User Avatar

The rms value of an ac voltage tells you the dc voltage that would produce the same power in a resistive load.

Power is I2R, so if I is varying with time, the average power over time is proportional to the average value of I2. The square-root of the average value of I2 tells you the current that would produce the same power if it were dc.

RMS voltage is always quoted for ac power supplies. For a sine-wave the rms value is 1/sqrt(2) times the peak voltage.

User Avatar

Wiki User

11y ago
User Avatar

To convert peak-to-peak values to RMS multiply by 0.35355339 150V P-P = 53.0330085V RMS

User Avatar

Wiki User

18y ago
User Avatar

A: Root Mean Suare and it is defined as .707 of the peak

User Avatar

Wiki User

14y ago
User Avatar

the difference between total negative and positive swing. so a 10vAC PtP will be 20vAC

User Avatar

Wiki User

14y ago
User Avatar

The average and RMS value of a square wave is the same as the peak voltage.

User Avatar

Wiki User

13y ago
User Avatar

Add your answer:

Earn +20 pts
Q: Rms value of sum of two sine waves?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Continue Learning about Engineering

What will be the Flowchart for adding all elements in an array in c plus plus?

It is not possible to show a flowchart in this website -- it is text only. The algorithm can be summarised as follows: int sum(std::array<int>& a) { int sum = 0; // initialise the return value for (auto i : a) // for each value in the array sum += i; // increment the sum by the value return sum; // return the sum }


How to Declare a variable that stores the cumulative sum java?

In Java:You declare the variable like this:int sum;If you want to include decimals, change this to:double sum;To store an initial value, just use the assignment operator:sum = 0;You can combine this with the declaration:double sum = 0.0;To add something to the variable, for example the value of a variable called "x", use one of the following:sum = sum + x;sum += x;In Java:You declare the variable like this:int sum;If you want to include decimals, change this to:double sum;To store an initial value, just use the assignment operator:sum = 0;You can combine this with the declaration:double sum = 0.0;To add something to the variable, for example the value of a variable called "x", use one of the following:sum = sum + x;sum += x;In Java:You declare the variable like this:int sum;If you want to include decimals, change this to:double sum;To store an initial value, just use the assignment operator:sum = 0;You can combine this with the declaration:double sum = 0.0;To add something to the variable, for example the value of a variable called "x", use one of the following:sum = sum + x;sum += x;In Java:You declare the variable like this:int sum;If you want to include decimals, change this to:double sum;To store an initial value, just use the assignment operator:sum = 0;You can combine this with the declaration:double sum = 0.0;To add something to the variable, for example the value of a variable called "x", use one of the following:sum = sum + x;sum += x;


Write a C program to accept a string from user and display its ascii value and then display sum of all ascii value of strings?

//C program to accept a string from user and //display its ascii value and //then display sum of all ascii value of strings #include<stdio.h> #include <string.h> int main() { char String[100]; int Sum,Index; Sum=0; //Sum is initially zero printf("Enter the string:\n"); gets(String); //Accept String from User for(Index=0;Index<strlen(String);Index++) { Sum+=(String[Index]); //Adds (the ASCII values of) the String characters. } printf("The sum is %d\n",Sum); //Printing it as %d gives the equivalent ASCII value. return 0; }


Write a program that reads an integer between 0 and 1000 and adds all the digits in the integer?

public class Add { public staticvoid main(String[] args) { int value=12; intcount=0; int sum=0; while(count


Why fourier series is used for frequency domain?

The fourier series relates the waveform of a periodic signal, in the time-domain, to its component sine/cosine frequency components in the frequency-domain. You can represent any periodic waverform as the infinite sum of sine waves. For instance, a square wave is the infinite sum of k * sin(k theta) / k, for all odd k, 1 to infinity. Using a Fourier Transformation, you take take a signal, convert it from time-domain to frequency-domain, apply some filtering or shifting, and convert it back to time-domain. Sometimes, this is easier than building an analog filter, even given that you need a digital signal processor to do it.