#include
#include
void main()
{
int rev num=0;
while(num>0)
{
rev num=rev num*10+num%10;
num=num%10;
}
return rev_num;
}
int main();
{
int num=4562;
printf("reverse of number is%d",reverse digit(num));
getch();
return o;
}
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write the javascript code to display the reverse no. of given no. (e.g. 247 reverse of 742)
To reverse a number, first convert the number to a string, then reverse the string. Given your number consists of alphanumeric characters, the number must already be a string so simply reverse the string: #include<string> using std::string; string reverse (const string& s) { string str {}; for (auto c : s) str.insert (str.begin(), c); return str; } int main () { std::cout << "Enter a number: "; string s {}; std::cin >> s; std::cout << "The number in reverse is: " << reverse (s); }
#include <stdio.h> #include<conio.h> void main () { int a,r,n,sum=0; clrscr(); printf("enter the number"); scanf("%d",& n); c=n while (n!=0) { a=n%10; n=n/10; sum=sum*a+a } printf("the reverse is %d \n",sum); if(c==sum) printf("\n the given number is palindrome"); else printf("\n the given number is not a palindrome"); getch(); }
//Reverse of the Number #include<stdio.h> #include<conio.h> int main () { int num,mod,rev=0; printf("Enter a number:"); scanf("%d", &num); while (num>0) { mod=num%10; rev=(rev*10)+mod; num=num/10; } printf("Reverse of the given number: %d", rev); getchar(); return 0; } // alternative solution based on reversing the alphanumeric representation of // the number: void rev(int me) { char alpha[32]; sprintf(alpha, "%d", me); for (const char* cp = alpha + strlen(alpha) - 1; cp >= alpha; --cp) { putchar(cp); } }
Pointer to Pointer is a double pointer, denoted by (**). Pointer stores the address of the variable and pointer to pointer stores the address of a pointer variable and syntax can be given as int **ptr2ptr;