write the javascript code to display the reverse no. of given no. (e.g. 247 reverse of 742)
#include <stdio.h> #include<conio.h> void main () { int a,r,n,sum=0; clrscr(); printf("enter the number"); scanf("%d",& n); c=n while (n!=0) { a=n%10; n=n/10; sum=sum*a+a } printf("the reverse is %d \n",sum); if(c==sum) printf("\n the given number is palindrome"); else printf("\n the given number is not a palindrome"); getch(); }
To reverse a number, first convert the number to a string, then reverse the string. Given your number consists of alphanumeric characters, the number must already be a string so simply reverse the string: #include<string> using std::string; string reverse (const string& s) { string str {}; for (auto c : s) str.insert (str.begin(), c); return str; } int main () { std::cout << "Enter a number: "; string s {}; std::cin >> s; std::cout << "The number in reverse is: " << reverse (s); }
//Reverse of the Number #include<stdio.h> #include<conio.h> int main () { int num,mod,rev=0; printf("Enter a number:"); scanf("%d", &num); while (num>0) { mod=num%10; rev=(rev*10)+mod; num=num/10; } printf("Reverse of the given number: %d", rev); getchar(); return 0; } // alternative solution based on reversing the alphanumeric representation of // the number: void rev(int me) { char alpha[32]; sprintf(alpha, "%d", me); for (const char* cp = alpha + strlen(alpha) - 1; cp >= alpha; --cp) { putchar(cp); } }
Pointer to Pointer is a double pointer, denoted by (**). Pointer stores the address of the variable and pointer to pointer stores the address of a pointer variable and syntax can be given as int **ptr2ptr;
reverse programe in fox pro
write the javascript code to display the reverse no. of given no. (e.g. 247 reverse of 742)
123
You write the number and then follow it with the digits in reverse order.
echo "enter the number" if [ $# -ne 1 ] then echo "Usage: $0 number" echo " I will find reverse of given number" echo " For eg. $0 12321, I will print 12321" exit 1 fi n=$1 rev=0 sd=0 while [ $n -gt 0 ] do sd=`expr $n % 10` rev=`expr $rev \* 10 + $sd` n=`expr $n / 10` done echo "Reverse number is $rev"
The reverse lookup is a telephone number data base. Instead of looking up a phone number based on a given name, a name can be looked up based on a given phone number. It is useful when receiving phone calls from an unknown phone number.
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A mirror prime.
#include <stdio.h> #include<conio.h> void main () { int a,r,n,sum=0; clrscr(); printf("enter the number"); scanf("%d",& n); c=n while (n!=0) { a=n%10; n=n/10; sum=sum*a+a } printf("the reverse is %d \n",sum); if(c==sum) printf("\n the given number is palindrome"); else printf("\n the given number is not a palindrome"); getch(); }
8086 assembly language program to check wether given number is perfect or not
To reverse a number, first convert the number to a string, then reverse the string. Given your number consists of alphanumeric characters, the number must already be a string so simply reverse the string: #include<string> using std::string; string reverse (const string& s) { string str {}; for (auto c : s) str.insert (str.begin(), c); return str; } int main () { std::cout << "Enter a number: "; string s {}; std::cin >> s; std::cout << "The number in reverse is: " << reverse (s); }
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