160 and 192.
The tricky part is getting the individual digits. There are basically two ways to do this: 1) Convert the number to a string, and use string manipulation to get the individual digits. 2) Repeatedly divide the number by 10. The digit is the remainder (use the "%" operator). To actually get the highest digit, initially assume that the highest digit is zero (store this to a variable, called "maxDigit" or something similar). If you find a higher digit, replace maxDigit by that.
Count them unless the number has a recurring ending.
The greatest number is infinity.
Yes
first you look at the first number tell what that number is then you just find the first digit.
syntax error
Compare one digit at a time, from left to right, until you find a digit that is different. The number with the greater digit in this position is the larger number.
find the diagonal method of two digit number and three digit number
No. Compare equivalent digits one by one, from left to right, until you find a digit where there is a difference. In this case, the number with the bigger digit in that position is also the bigger number.
Look for the first digit that is different. In this case, the first digit after the decimal point. The number that has the larger digit in this position, is larger. If the first digit is the same, compare the second digit with the second digit, the third digit with the third digit, and so forth, until you find a difference.
"If the units digit and the hundreds digit of the number 513 were reversed..." 315 'find the sum of the original number and the new number." 513+315=828
The last digit is always the estimated digit in a number
It is 63.
It is 99,899,999.
The units digit of a two digit number exceeds twice the tens digit by 1. Find the number if the sum of its digits is 10.
50