Every class requires at least one constructor, the copy constructor. It is implied if not declared. If no constructors are declared, a default constructor is also implied. Every class also requires a destructor, which is also implied if not declared.
The purpose of constructors is to construct the object (obviously) but by defining your own you can control how the object is constructed, and how member variables are initialised. By overloading constructors, you allow instances of your object to be constructed in several different ways.
The copy constructor's default implementation performs a member-wise copy (a shallow-copy) of all the class members. If your class includes pointers, you will invariably need to provide your own copy constructor to ensure that memory is deep-copied. That is, you'll want to copy the memory being pointed at, not the pointers themselves (otherwise all copies end up pointing to the same memory, which could spell disaster when one of those instances is destroyed).
The destructor allows you to tear-down your class in a controlled manner, including cleaning up any memory allocated to it. If your class includes pointers to allocated memory, you must remember to delete those pointers during destruction. The destructor is your last-chance to do so before the memory "leaks". The implied destructor will not do this for you -- you must implement one yourself.
class foo
{
public:
foo(){} // Default constructor.
foo(const foo & f){} // Copy constructor.
~foo(){} // Destructor.
};
A default constructor is one that has no parameters (C++ also calls constructors with all default parameters a default constructor), while a parameterized constructor is one that has at least one parameter without a default value. Default constructors can be provided by the compiler if no other constructors are defined for that class or any class the class inherits from, while parameterized constructors must always be defined by the developer.
default constructor is used only when the programmer does not use a constructor to initialize objects. Once the programmer defines a constructor then the default constructor is no longer used
True - A C++ constructor cannot return a value.
An implicit constructor call will always call the default constructor, whereas explicit constructor calls allow to chose the best constructor and passing of arguments into the constructor.
A parameterized constructor in java is just a constructor which take some kind of parameter (variable) when is invoked. For example. class MyClass { //this is a normal constructor public MyClass(){ //do something } //this is a parameterized constructor public MyClass(int var){ //do something } //this is another parameterized constructor public MyClass(String var, Integer var2){ //do something } }
There is no such thing as a default parameterized constructor. The default constructor is always the 'no-arg' constructor and does not take any parameters or arguments as input
A default constructor is one that has no parameters (C++ also calls constructors with all default parameters a default constructor), while a parameterized constructor is one that has at least one parameter without a default value. Default constructors can be provided by the compiler if no other constructors are defined for that class or any class the class inherits from, while parameterized constructors must always be defined by the developer.
default constructor is used only when the programmer does not use a constructor to initialize objects. Once the programmer defines a constructor then the default constructor is no longer used
Yes.
True - A C++ constructor cannot return a value.
An implicit constructor call will always call the default constructor, whereas explicit constructor calls allow to chose the best constructor and passing of arguments into the constructor.
A parameterized constructor in java is just a constructor which take some kind of parameter (variable) when is invoked. For example. class MyClass { //this is a normal constructor public MyClass(){ //do something } //this is a parameterized constructor public MyClass(int var){ //do something } //this is another parameterized constructor public MyClass(String var, Integer var2){ //do something } }
No. Constructors initialise objects and, by definition, must be able to modify the member variables. Uninitialised members are a disaster waiting to happen even without a constructor declared const! Thankfully, the compiler won't permit a const constructor.
A parameterized constructor is one that takes multiple arguments/parameters as input. Ex: let us say we want to create multiple constructor for a class Test Public class Test { Public Test() { //code } Public Test(int vals) { //code } Public Test(String val) { //code } }
A constructor is a method that fires when the object is instantiated. A friend function is a function that has special access to the object. They are two different types of things, and cannot be further differenced.
The default constructor is an empty (only call the super constructor) with no parameters constructor inserted by the java compiler when you don't define a constructor in your class. If you write something like this: public class NoConstructorClass{ //no constructor goes here } Then you get something like this: public class NoConstructorClass{ public NoConstructorClass(){ // Default constructor that you didn't write super(); } }
It cannot. Inheritance is a compile-time operation. Constructors are invoked at runtime at the point of instantiation.