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9c is.
c2+6c+9 = (c+3)(c+3)
3v... 1j=1v*1c
14c + c + 12 = 15c + 12 = 3(5c + 4)
You will need to use this table to obtain the 5 Bit symbols.4-Bit 5-Bit Code0000 111100001 010010010 101000011 101010100 010100101 010110110 011100111 011111000 100101001 100111010 101101011 101111100 110101101 110111110 111001111 11101