9c is.
c2+6c+9 = (c+3)(c+3)
3v... 1j=1v*1c
14c + c + 12 = 15c + 12 = 3(5c + 4)
You will need to use this table to obtain the 5 Bit symbols.4-Bit 5-Bit Code0000 111100001 010010010 101000011 101010100 010100101 010110110 011100111 011111000 100101001 100111010 101101011 101111100 110101101 110111110 111001111 11101
It IS expanded.
about 78 to get a level 5c
The only common factor of 10a and 5b is a 5. So the factored form will be something like: 5(2a _ b) assuming the _ is filled in with the proper operation (+ - * / etc.). If the original expression is 10a + 5b, the answer would be 5(2a + b).
A level 5a is higher. This is how it works: n 1c 1b 1a 2c 2b 2a 3c 3b 3a 4c 4b 4a 5c 5b 5a ect. Student from BGP. N.S.S
ks3 means key stage 3
5b + 5b = 2 x 5b
Considered level 4 is average for someone in year 6 and level 5/6 is average for someone in year 9 I would say 4C-5B level 7 is above average.
duuugh type in google : ks3 vocab duuugh duuugh
The GCF is 5b.
no
2a+5b isn't possible the answer is still 2a+5b.
These days, lots of secondary schools in England are starting to settle for a level 4a. The truth is, I am in a school that specialises in business and enterprise and in some cases, a level 5b at the end of year 7 may place you in top set for year 8. I achieved a level 6c at the end of year 7 and ended up in top set for year 8. Really, a 4a, 5c or 5b is average; occasionally a 5b may be high.