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In a java statement Math.sqrt what is Math and what is sqrt?

Anonymous

∙ 14y ago

Updated: 10/18/2022

Math is the class, and sqrt() is the method.

Wiki User

∙ 14y ago

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Q: In a java statement Math.sqrt what is Math and what is sqrt?

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How do you square root in java?

knioubuhy yig hnm vuigvgh ujhb jhbihjbnihkjlkmmnlk

What's the square root of 3 times the square root of 15?

3.4086580994024981055126631335409sqrt(3)= 1.7320508075688772935274463415059sqrt(15) = 3.8729833462074168851792653997824sqrt(3) x sqrt(15) = 6.7082039324993690892275210061938 = sqrt(45) = 3 x sqrt(5)AnswerThis is an example of a question that's ambiguous because it hasn't been written mathematically. The above answer is for sqrt(3) x sqrt(15). Another interpretation of the question would be sqrt(3 x sqrt(15)), which has a different answer.

How do you calculate VAC?

Vtop = sqrt(2)*Veffective so Veffective = Vtop / sqrt(2)

What is d command for square root in C programming in Linux?

No commands in C; the name of function sqrt is sqrt (include math.h; and use -lm at linkage)

What does sqrt function return?

square root of the argument

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Related Questions

What is sqrt 2 plus sqrt 2?

Approximately 2.828427

How do you simplify the square root of 8?

sqrt 8 = sqrt 4 x 2 = 2 sqrt 2 But you wouldn't use "sqrt" to replace the proper math sign

How do you square root in java?

knioubuhy yig hnm vuigvgh ujhb jhbihjbnihkjlkmmnlk

Is the sqrt 7 a whole number?

is the number 7 in real math a whole number

Is the square root of 38 rational or irrational?

Well, isn't that just a happy little question! The square root of 38 is actually an irrational number because it cannot be expressed as a simple fraction. It's like a beautiful little mystery in the world of numbers, just waiting to be explored and appreciated. Just remember, there's no mistakes in math, only happy little accidents!

What is the radical of the figure 165?

It is a Kangxi radical. The best way to display this radical is: sqrt(11)*sqrt(5)*sqrt(3). To get more information on these kinds of radicals one could visit websites such as Cool Math.

Using imaginary i simplify the square root of negative 48?

Oh, dude, imaginary numbers? Like, sure, let's do this. So, the square root of negative 48 can be simplified as 4i√3. It's like regular math, but with a little twist of imagination. So, there you have it, imaginary math for the win!

What is the square root of 7.2?

Expressed as a surd in its simplest form, sqrt(7.2) = 6 sqrt(5)/5 Expressed as a decimal, rounded to two decimal places, sqrt(7.2) = Â±2.68

What is the square root of 72 using radicals?

sqrt(72) = sqrt(36*2) = sqrt(36)*sqrt(2) = 6*sqrt(2).sqrt(72) = sqrt(36*2) = sqrt(36)*sqrt(2) = 6*sqrt(2).sqrt(72) = sqrt(36*2) = sqrt(36)*sqrt(2) = 6*sqrt(2).sqrt(72) = sqrt(36*2) = sqrt(36)*sqrt(2) = 6*sqrt(2).

What are the first 16 equations for the wheel of theodorus?

sqrt(1^2 + 1^2 ) = sqrt(2)sqrt(sqrt(2)^2 + 1^2 ) = sqrt(3)sqrt(sqrt(3)^2 + 1^2 ) = sqrt(4)sqrt(sqrt(4)^2 + 1^2 ) = sqrt(5)sqrt(sqrt(5)^2 + 1^2 ) = sqrt(6)sqrt(sqrt(6)^2 + 1^2 ) = sqrt(7)sqrt(sqrt(7)^2 + 1^2 ) = sqrt(8)sqrt(sqrt(8)^2 + 1^2 ) = sqrt(9)sqrt(sqrt(9)^2 + 1^2 ) = sqrt(10)sqrt(sqrt(10)^2 + 1^2 ) = sqrt(11)sqrt(sqrt(11)^2 + 1^2 ) = sqrt(12)sqrt(sqrt(12)^2 + 1^2 ) = sqrt(13)sqrt(sqrt(13)^2 + 1^2 ) = sqrt(14)sqrt(sqrt(14)^2 + 1^2 ) = sqrt(15)sqrt(sqrt(15)^2 + 1^2 ) = sqrt(16)sqrt(sqrt(16)^2 + 1^2 ) = sqrt(17)

What is the simplest square radical form for 50 and 3 square root of 8?

sqrt(50) = sqrt(25*2) = sqrt(25)*sqrt(2) = 5*sqrt(2)3*sqrt(8) = 3*sqrt(4*2) = 3*sqrt(4)*sqrt(2) = 3*2*sqrt(2) = 6*sqrt(2).sqrt(50) = sqrt(25*2) = sqrt(25)*sqrt(2) = 5*sqrt(2)3*sqrt(8) = 3*sqrt(4*2) = 3*sqrt(4)*sqrt(2) = 3*2*sqrt(2) = 6*sqrt(2).sqrt(50) = sqrt(25*2) = sqrt(25)*sqrt(2) = 5*sqrt(2)3*sqrt(8) = 3*sqrt(4*2) = 3*sqrt(4)*sqrt(2) = 3*2*sqrt(2) = 6*sqrt(2).sqrt(50) = sqrt(25*2) = sqrt(25)*sqrt(2) = 5*sqrt(2)3*sqrt(8) = 3*sqrt(4*2) = 3*sqrt(4)*sqrt(2) = 3*2*sqrt(2) = 6*sqrt(2).

What is the square root of A squared B plus the square root of A B squared divided by the square root of AB?

The question is ambiguous because it could refer to [sqrt(A2B) + sqrt(AB2)]/sqrt(AB) = [A*sqrt(B) + B*sqrt(A)]/[sqrt(A)*sqrt(B)] = A/sqrt(A) + B/sqrt(B) = sqrt(A) + sqrt(B) or sqrt(A2B) + sqrt(AB2)/sqrt(AB) = A*sqrt(B) + B*sqrt(A)/[sqrt(A)*sqrt(B)] = A*sqrt(B) + B/sqrt(B) = A*sqrt(B) + sqrt(B) = sqrt(B)*(1 + A)

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