Inductive. Used to remember this by "Eli" the "ice" man. "(e) Voltage (l) (Inductive circuit) (i) current", the ,"(i) Current (c) (capacitive circuit) (e) voltage, man.
There is no true advantage of RC circuits over RL circuits, as they perform different functions. RC circuits contain resistors and capacitors, while RL circuits contain resistors and inductors.
Because the voltage across the capacitor is initially zero, making the voltage across the resistor maximal. As the capacitor charges, the voltage across the resistor decreases, with an accompanying reduction in current. At maximum charge, the voltage across the resistor is zero, and thus there is no current.The equation of a capacitor is ...dv/dt = i/c... meaning that the rate of change of voltage, in volts per second, is proportional to current, in amperes, and inversely proportional to capacitance, in farads.Set this up into a series charging circuit, replacing the i term with (V-Vt) / R, solve the differential equation, and you get ...Vt = VSource (1 - e-t/RC).... where Vt is voltage at some time t, and RC is the time constant, resistance times capacitance.The is the DC state answer. AC circuits are a whole other issue, and require different analysis, though the fundamental equation remains the same.
0.63 is the knee voltage & 0.37 is the cutoff voltage
It increases. The time constant of a simple RC circuit is RC, resistance times capacitance. That is the length of time it will take for the capacitor voltage to reach about 63% of a delta step change. Ratio-metrically, if you double the resistance, you will double the charge or discharge time.
There is no power loss in open circuit test. Actually there is iron loss also known as magnetic losses. These include hysteresis and eddy-current losses. This can be described as V1^2/Rc Where V1 is the primary voltage and Rc is the resistance of the magnetic core.
RL circuit consists of a resistor and an inductor connected in series, while an RC circuit consists of a resistor and a capacitor connected in series. In an RL circuit, the time constant is determined by the resistance and inductance, while in an RC circuit, the time constant is determined by the resistance and capacitance. RL circuits respond to changes in current, while RC circuits respond to changes in voltage.
If you understand complex numbers then you will see that the imaginary value jXC which depends upon the value of C,capacitance, determines the value of the phase displacement angle.Answer">AnswerYou don't need to understand complex numbers to understand this topic. The term you are looking for is 'phase angle', not 'phase difference'. This is defined as the angle by which the load current leads or lags the supply voltage. For a resistive-capactive circuit, the load current leads the supply voltage and, so, the phase angle is leading. The actual angle depends on the values of R and XC (capacitive reactance). Incidentally, the 'displacement angle' is something different again!
RC circuits can be used to filter a signal by blocking certain frequencies and passing others.
There is no true advantage of RC circuits over RL circuits, as they perform different functions. RC circuits contain resistors and capacitors, while RL circuits contain resistors and inductors.
If you double the the RC circuit input frequence, the magnitude of voltage and current depends on whether or not the RC circuit is configured low-pass or high-pass, and on whether or not the original frquency is close to the knee frequency (the -3db point). The question has insufficient information to be answered completely.
Because the voltage across the capacitor is initially zero, making the voltage across the resistor maximal. As the capacitor charges, the voltage across the resistor decreases, with an accompanying reduction in current. At maximum charge, the voltage across the resistor is zero, and thus there is no current.The equation of a capacitor is ...dv/dt = i/c... meaning that the rate of change of voltage, in volts per second, is proportional to current, in amperes, and inversely proportional to capacitance, in farads.Set this up into a series charging circuit, replacing the i term with (V-Vt) / R, solve the differential equation, and you get ...Vt = VSource (1 - e-t/RC).... where Vt is voltage at some time t, and RC is the time constant, resistance times capacitance.The is the DC state answer. AC circuits are a whole other issue, and require different analysis, though the fundamental equation remains the same.
The RC circuit can reduce the phase shift between the voltage and current in the power line. The phase shift is caused by the inductance of the motor. The phase shift between the voltage and current in the power line causes problems due to the presence of so called imaginary current or power that does no work but must be supplied by the power source.
0.63 is the knee voltage & 0.37 is the cutoff voltage
Capacitors do not get "full" like a glass of water. The current into a capacitor is the rate of change of charge, so it's equal to C * dV/dt or something. If the voltage is constant, there's no current. If the voltage on both sides of the resistor is the same, there's no current through the resistor and hence into the capacitor, so that's the steady-state - what you call "full" - the capacitor charged to the supply voltage.
Uhhh... the short answer is "everywhere".
If there are only a resistor and a capacitor in the circuit, then the phase shift will indeed be between 0 and 90 degrees. When the resistor and capacitor are in series, the phase shift will be negative when the capacitor is connected to a source voltage and the resistor is the load. The phase shift will be positive when the resistor is connected to the source. The lower the values of R and C, the higher the frequency bandwidth.With the resistor and capacitor connected in series and the two parts connected to a current source, the phase shift will be negative. At high frequencies, the output voltages is lower, and the circuit appears as a very low impedance. At low frequencies, the circuit looks more like a resistor. Again, the phase shift will be between 0 and 90 degrees.CommentThe correct term is phase angle, not 'phase shift'. By definition, the phase angle is the angle by which the load current leads or lags the supply voltage. For an RC circuit, the current leads the voltage, so the phase angle is a leading phase angle.
It increases. The time constant of a simple RC circuit is RC, resistance times capacitance. That is the length of time it will take for the capacitor voltage to reach about 63% of a delta step change. Ratio-metrically, if you double the resistance, you will double the charge or discharge time.