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Swapping two values in a single statement is made possible through a series of three XOR/assign operations, alternating the operands.


Consider the following declarations:


int x = 0;

int y = 1;


The following statement will swap the values of x and y:


x ^= y ^= x ^= y; // swap



The same statement implemented as a function:


void swap(int &x, int &y){ x ^= y ^= x ^= y; }





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11y ago
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15y ago

Depending on your compiler, you may be able to use:

a = a+ b - (b = a);

This seems to work with gcc.

Using Microsoft's cl.exe (c++) gives the following output:

before swap: a = 5, b = 21

after swap: a = 5, b = 5

If this line does not work, another option would be to use your one line to make a function call, something like: void swap(int &x, int &y) { int temp = x; x = y; y = temp; }

int main() { int a = 10, b = 34; cout << "before swap: a = " << a << ", b = " << b << endl;

swap(a, b);

cout << "after swap: a = " << a << ", b = " << b << endl; return 0; }

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15y ago

a=a+b-(b=a); // Swaps variables a and b

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13y ago

temp=a; a=b; b=temp;

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Q: How should you Swap 2 numbers in a single line?
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